## I am having problem using hex2dec. It shows an error when it is used.

### Suhas Holla (view profile)

on 24 Mar 2013

I am using MATLAB R2009. And I have problem using hex2dec. I am permutating a the row element after using dec2hex, and then using hex2dec. and it show the following error message.

```Error using ==> hex2dec at 38
Input string found with characters other than 0-9, a-f, or A-F.
```
```Error in ==> crypt_d at 62
td8=hex2dec(td8);
```

when i check the td8 variable the element which has zeros has been replaced by empty space as in

```td8
```
```td8 =
```
```0C F 9
```

the space between C and F and F and 9 is supposed to be zeros. Can anyone please tell how to overcome these problem.

this is the part of the code where error is occurring

```for i=1:si
td8=de_hex4(i,:);
td8=hex2dec(td8);
end
```

## Products

### the cyclist (view profile)

on 24 Mar 2013
Edited by the cyclist

### the cyclist (view profile)

on 24 Mar 2013

I am not sure where you got the variable de_hex4, but if you are confident that all you need to do is replace the spaces with zeros, then you can do that with the regexprep function:

```td8 = regexprep(td8,' ','0');
```

before you then send it to hex2dec.

Walter Roberson

### Walter Roberson (view profile)

on 24 Mar 2013

I think de_hex4 is a variable, but I do not know what was assigned to it.

the cyclist

### the cyclist (view profile)

on 24 Mar 2013

You are right. I wrote function instead of variable. I have edited.

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