Asked by Yuval
on 27 Mar 2013

I am trying to plot six concentric circles using meshgrid() and plot(). The circles' radii vary between 0.5 and 1.75 (with intervals of 0.25). I am wondering whether the code below is sufficiently efficient and whether indeed it should be performed as delineated below:

theta = linspace(0, 2*pi, 50); [X, Y] = meshgrid(0.5:0.25:1.75, theta); plot(a+cos(Y).*X, b+sin(Y).*X);

?

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Answer by Matt J
on 27 Mar 2013

Accepted answer

You could conserve a little memory if you did it this way, but I don't know anyone who cares about efficiency for such a small plotting task,

theta = linspace(0, 2*pi, 50).'; R=0.5:0.25:1.75;

plot(a+cos(theta)*R, b+sin(theta)*R);

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Matt J
on 27 Mar 2013

You mean you ran my code exactly, but with the transpose omitted and everything worked fine? I don't think so. You should have gotten a dimension mismatch error as I do below

Error using * Inner matrix dimensions must agree.

Error in test (line 6) plot(a+cos(theta)*R, b+sin(theta)*R);

And it's perfectly clear why this happens. Matrix multiplication between 2 row vectors together like cos(theta) and R or sin(theta) and R is undefined.

Yuval
on 27 Mar 2013

I mean I ran mine, the original one I posted here, in which the transpose was clearly omitted, and yet the plot was just as that generated by your own code, with the transpose. Is that still impossible? Did you mean to suggest that that is strictly mandatory if R is defined as you proposed? Please allow me to re-post what works perfectly fine on this machine:

theta = linspace(0, 2*pi, 50); R = 0.5: 0.25: 1.75; [X, Y] = meshgrid(R, theta); plot(a+cos(Y).*X, b+sin(Y).*X);

Matt J
on 27 Mar 2013

Opportunities for recent engineering grads.

## 1 Comment

## Image Analyst (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/68765#comment_139208

Yeah - it does, but so? What is the question?