Asked by S
on 7 Apr 2013

x1=7.8; x2=8.5; y1=0.96; y2=0.94; p1 = polyfit([x1 x2], [y1 y2], 2); b1= polyval(p1,1); m1=polyval(p1,2)-b1; x3=8.25; x4=8.25; y3=0; y4=.99; p2 = polyfit([x3 x4], [y3 y4], 2); b2 = polyval(p2, 1); m2 = polyval(p2, 2) - b2;

I got x value = -1.2867; from which co-ordinate this value corresponds to? Actually I want to compute intersection of two line with respect to x=[7.8 8.25 8.5]; y=[0.96 0.99 0.94]; over which those two lines are plotted?

x=[7.8 8.25 8.5]; y=[0.96 0.99 0.94]; p=polyfit(x,y,2); f=polyval(p,x); plot(x,y,'o',x,f,'-'); hold on; line([7.8 8.5],[0.96 0.94]); hold on; line([8.25 8.25],[0 0.99]);

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## 2 Comments

## Image Analyst (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/70427#comment_141684

Do you want to do it numerically (using quantized arrays), or analytically (using algebraic equations)? Why did you tag this as digital image processing?

## S (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/70427#comment_145821

I want numerically.