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calculate distance using the below equation

Asked by Elysi Cochin on 11 Apr 2013

i have 2 variables, dataMatrix and queryMatrix..... dataMatrix contains 245 rows and 38 column values...... and queryMatrix contains 1 row and 38 column values...... i calculate the euclidean distance and sort the distances in ascending order as below.....

```    for w=1:245
dist = sum((repmat(queryMatrix(w,:),245,1)-dataMatrix).^2,2);
[sortval sortpos] = sort(dist,'ascend');
neighborIds(w,:) = sortpos(1:k);
neighborDistances(w,:) = sqrt(sortval(1:k));
end```

instead of euclidean distance i want to use the distance formula in the below link.....

http://img28.imageshack.us/img28/3595/distanceu.png

but i dont know to write the equation in matlab...... please can someone convert that equation to matlab..... it would be great help to me..... please do reply......

1 Comment

Matt J on 11 Apr 2013

If queryMatrix only has 1 row, how can w run from 1 to 245 in queryMatrix(w,:)?

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Answer by Matt J on 11 Apr 2013

Assuming queryMatrix and dataMatrix are both 245x38, the whole thing can be done without loops,

```    d=permute(dataMatrix,[1,3,2]);
q=permute(queryMatrix,[3,1,2]);```
```    num = abs(bsxfun(@minus,d,q));
den =  bsxfun(@plus,abs(d),abs(q));```
`    dist=sum(num./den,3);`
```    [sortval sortpos] = sort(dist);
neighborIds = sortpos(1:k,:);
neighborDistances = sqrt(sortval(1:k,:));```

Elysi Cochin on 11 Apr 2013

sir what is 1,3,2 and 3,2,1 in

```    d=permute(dataMatrix,[1,3,2]);
q=permute(queryMatrix,[3,1,2]);```

shud i use it in my datavalues???..... as my datavalues are not of the same row and column values.... what changes should i make when i use for loop?? please do reply sir....

Matt J on 11 Apr 2013

To understand the syntax of the PERMUTE command, see

``` doc permute
help permute```

As I mentioned, you don't need to be using a for-loop. The only requirement here is that dataMatrix and queryMatrix have the same number of columns.

Answer by Andrei Bobrov on 11 Apr 2013
Edited by Andrei Bobrov on 11 Apr 2013
```dataMatrix = randi([-10,10],10,5);
queryMatrix = randi([-10 10],1,5);
```
```d = bsxfun(@(x,y)abs(x - y)./(abs(x) + abs(y)),...
dataMatrix,permute(queryMatrix,[3 2 1]));
d = sort(squeeze(sum(d,2)));
```

Elysi Cochin on 11 Apr 2013

sir in my code should i use for loop??? because when i do without for loop i'm getting all values NaN......

``` dataMatrix = dataMatrix.*sign(rand(size(dataMatrix)));
queryMatrix = queryMatrix.*sign(rand(size(queryMatrix))-.5);```

shud i use this rand function for my set of values??

Elysi Cochin on 12 Apr 2013

thank u all...