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use of msgbox in matlab

Asked by Locks on 11 Apr 2013

hi,

I tried to use the msgbox function in matlab, which I found here:

http://www.mathworks.ch/ch/help/matlab/ref/msgbox.html

I tried to take the formula to display at which i we are currrently with the code:

h = msgbox(i)

unfortunately it's not working at all. From VBA I know that it's just necessary to enter msgbox and the variable, but that doesn't work either

what do I need t change?

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Locks

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3 Answers

Answer by Image Analyst on 11 Apr 2013
Edited by Image Analyst on 11 Apr 2013
Accepted answer

You need to pass it a string

for k = 1 : 10
	message = sprintf('k = %4d\n', k);
	uiwait(msgbox(message));
	% You can use fprintf() instead if you don't want to prompt the user.
	fprintf(message); % Goes to command window.
end

Or better yet, use questdlg() so the user can have an opportunity to break out of your 1000 iteration loop:

for k = 1 : 10
	message = sprintf('k = %4d\nContinue?', k);
	reply = questdlg(message, 'Continue', 'OK', 'Cancel', 'OK');
	if strcmpi(reply, 'Cancel')
		% User said Cancel, so exit.
		break;
	end
end

I used k as a loop variable because you're not supposed to use i or j - they're the imaginary variable.

1 Comment

Locks on 12 Apr 2013

thanks, that helps!

Image Analyst
Answer by per isakson on 11 Apr 2013
Edited by per isakson on 11 Apr 2013
    >> h = msgbox('This is my message') 
    h =
        0.0012
    >> 

works fine here. Message should be a string.

[Added:] To show the value of the numeric variable: i

     h = msgbox( num2str( i ) ) 

VB do things more automagically than Matlab. Here you need to do the conversion explicitely.

0 Comments

per isakson
Answer by Locks on 11 Apr 2013

What do I need to do if I would like to see which value the i has, which runs form 1 to 1000?

1 Comment

per isakson on 11 Apr 2013

Se my answer above.

Locks

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