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Samadar Salim

how to solve loops conditions ??

Asked by Samadar Salim
on 20 Apr 2013

any one can help me for this homeworke i couldnt solve

use loops or/and Condition statements to creat this matrix

   1   2  3  4  5
   6   7  8  9  10 
A= 11 12 13  14 15
   16 17 18  19 20
   21 22 23  24 25
   26 27 28  29 30

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2 Answers

Answer by Walter Roberson
on 20 Apr 2013
for K = 1 : 1
  A = reshape( 1:30, 5, 6 ) .';
end

  1 Comment

Ahmed A. Selman
on 21 Apr 2013

What is for k = 1 : 1 doing here, when it's from 1 to 1 and A is k independent?


Answer by Ahmed A. Selman
on 21 Apr 2013

#1) Using for loops only:

clear
k=0;
for i=1:6
    for j=1:5
    k=k+1;
    A(i,j)=k;
    end 
end 
disp(A)

#2) Using for loop with if statement:

clear 
clc
k=0;
j=1;
for i=1:30
    k=k+1;
    A(j,k)=i;
    if fix(i/5)==(i/5)
        j=j+1;
        k=0;
    end 
end 
disp(A)

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