How do you count how many values are in an array until a given number?
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I have an array of values, it starts with integers then some zeros appear before finally more integers and then more zeros. I am looking to find a way to cut the array short before the second set of zeros appear.
The minimum value always occurs in column 5 of the second set of integers so I thought I could find the minimum value and cut if off there, however to do this I need to know how what row this minimum number occurs at. Ive seen in some forums that the find function may be able to be used however I cant get it to work. An extract of my script is posted below.
data = csvread(['groupC0',num2str(i),'.CSV'],6,0);
limit = find(data,min(data(:,5)))
truedata = data(1:limit,3:8);
1 Comment
Jan
on 24 Apr 2013
The text description of the inputs is not clear. Are you talking about a vector or a matrix? If it is a matrix, do the zero blocks have the same position in each row (or column?)?
Accepted Answer
Jan
on 24 Apr 2013
x = [1,2,3,4,5,0,0,0,0,4,3,2,4,2,0,0,0,0,4,3,2]; % Does this match your data?!
zeroBlockStart = strfind(x == 0, [false, true]) + 1;
Now you have the indices, where the blocks of zeros start. Does this help already?
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