MATLAB attempted to access x(1,3), index out of bounds because numel(x)=1.

clc
clear all
x=0;
D=zeros(154);
for i=1:248
  D(x(i,1),x(i,2))=x(i,3);
end
D1=D+D';
for i=1:154
  for j=1:154
      if D1(i,j)==0
          D1(i,j)=inf;
      end
  end
end
for i=1:154
  for j=1:154
      if i==j
          D1(i,j)=0;
      end
  end
end

HOW IT HAPPEND= = AND I WANNA KNOW HOW TO CORRECT.DO ME A FAVOR I WILL APPRECIATE FORERVER,BECAUSE THE CODE CONNECTS WITH ONE IMPORTANT TEST.HELP!!!

[Matt Kindig]

Please format your code by highlighting it, and then clicking the '{} Code' button above. We cannot read/run your code as it is written.

[Matt Kindig]

x=0 creates a variable that is 1x1 (1 row, 1 column) in size. Thus, accessing x(i,3) throws an error, since x does not have 3 columns.

[Matt Kindig]

By the way, exactly what is your code supposed to do? By setting elements of D to x (which == 0), you are just setting D = 0. However, you already have a matrix of zeros with the D=zeros(154) line. The D1=D+D' line then gives D1 as a matrix of zeros as well.

What you you expect D1 to look like?

[sally]

SORRY !!I CAN'T GET IT..I WONDER IF YOU COULD CORRECT ME= =

[Azzi Abdelmalek]

I've edited your code twice, and you are making it each time unreadable

[sally]

so what do to do..A FRESHMAN IS A TRAGEDY

[Walter Roberson]

Duplicates by later http://www.mathworks.co.uk/matlabcentral/answers/74170-how-to-correct-attempted-to-access-x-1-3-index-out-of-bounds-because-numel-x-1 which also has discussion. Discussion should continue here instead of there.

Answer 1

[Azzi Abdelmalek]

Because you set x to 0, which means its length is 1, you can not use

x(i,1)

with i>1

[sally]

e..I should used with i>1 not x(i,1)?

[Azzi Abdelmalek]

what is x?

[sally]

sorry...I don't know how to correct..I AM A FRESHMAN= =