HOW TO CORRECT attempted to access x(1,3), index out of bounds because numel(x)=1.

clc
clear all
x=0;
D=zeros(154);
for i=1:248
  D(x(i,1),x(i,2))=x(i,3);
end
D1=D+D';
for i=1:154
  for j=1:154
      if D1(i,j)==0
          D1(i,j)=inf;
      end
  end
end
for i=1:154
  for j=1:154
      if i==j
          D1(i,j)=0;
      end
  end
end

I JUST WANNA KNOW HOW TO CORRECT.... I FEEL I WILL BE CRAYZY(wuwuwu)

[Cedric]

The line

 x = 0 ;

defines x as a scalar (1 element). Three lines below, you index it with

 D(x(i,1),x(i,2)) = x(i,3) ;

where you try to access elements (1,2) and (1,3) of x, which do not exist.

There is no correction, because even if I were telling you to define x as a 248x3 array ..

• You would use components of x that would be zeros to index D.
• Even if it were working, the FOR loop would redefine D as zero, which is what it is anyway after you initialize it using D=zeros(154).

[sally]

HOW TO CORRECT= =

[sally]

SO I SHOULD CHANGE THE HOLD CODE?

[sally]

I NEED YOUR HELP?I DON'T KNOW WHAT TO DO NEXT...

[Cedric]

You should first switch to lower case when you write on the forum. Then, I am not saying that you should change the whole code but .. what are you trying to do exactly?

[sally]

I WANT TO MAKE A 154*3 TABLE TO Adjacency matrix .

[Cedric]

As I said above: you should first switch to lower case when you write on the forum.

Then, how much time do you have for building this adjacency matrix? Is it for a homework, a longer term project, a Master/Ph.D. thesis?

EDIT: I'm off for the night; anyway, you want x to be a 248x3 array before the first FOR loop starts, not 0 as you defined it. Moreover, the first two columns of x must be positive integers below or equal to 154 (ID of vertices I guess).

Then, the rest should work, but the two nested FOR loop statements can be done way more efficiently (in one line each). We can talk about this, but you'll have to answer my question about the time frame and the nature of this work first.

[Walter Roberson]

Duplicates earlier http://www.mathworks.co.uk/matlabcentral/answers/74151-matlab-attempted-to-access-x-1-3-index-out-of-bounds-because-numel-x-1 which also has discussion. Further discussion should go there.