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mhowell

Attempted to access x(2); index out of bounds because numel(x)=1. But I'm using a matrix?

Asked by mhowell
on 4 May 2013

I'm just trying to execute a simple for loop, but I keep getting this error "Attempted to access x(2); index out of bounds because numel(x)=1.

Error in Quiz (line 11) x = x(i)" I don't understand what the error means. Any help would be appreciated!

x = [22.5 45 67.5 90]
 for i=1:4
    x = x(i)
    a = a(x)
    c = c(x)
    alpha = alpha(x)
    mu(a,c)
end

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2 Answers

Answer by Azzi Abdelmalek
on 4 May 2013
Edited by Azzi Abdelmalek
on 4 May 2013
 Accepted answer

After one itteration

for i=1:4
  x = x(i)

the length of x becomes equal to 1, then x(2) does not exist

  0 Comments


Answer by Iman Ansari
on 4 May 2013

Hi.

You change your x in first loop :

x = x(i) ====> x=22.5

after this x became a number.

  3 Comments

mhowell
on 4 May 2013

That makes sense. So how do I go about calling all the values of the matrix into my for loop?

Iman Ansari
on 4 May 2013

Use another variable:

y = [22.5 45 67.5 90]
y(2)
n = [1 3 5 7]
for i=1:4
  x = y(i)
  a = a(x)
  c = c(x)
  alpha = alpha(x)
  mu(a,c)
end
mhowell
on 4 May 2013

Thanks!!!


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