dividing a column matrix based on the no
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i have a single column matrix A=0 0 0 1 1 1 1 0 0 0 0 2 2 2 2 0 0 0 0 now i have to divide this in to several matrices such whenever 0 changes to 1 or 2 i want a new matrix in this case A1= 1 1 1 1 0 0 0 0; A2=2 2 2 2 0 0 0 0 which are also single column matrices
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Accepted Answer
Oleg Komarov
on 16 May 2011
A = [0 0 0 1 1 1 1 0 0 0 0 2 2 2 2 0 0 0 0].';
Split sequence (transforming in string)
out = regexp(sprintf('%d',A) ,'(1+0+|2+0+)','match');
Convert to double and store in cell array
c = cellfun(@(x) x.'-'0',out,'un',0)
c{1} % to retrieve the value
Organize eventually in structure with dynamic fields A001, A002, ..., An
numC = numel(c);
s = cell2struct(c, reshape(sprintf('A%03d', 1:numC),4,[]).',numC);
s.A001 % to retrieve the value
EDITED
With a loop
A = [0 0 0 1 1 1 1 0 0 0 0 2 2 2 2 0 0 0 0].';
c = 0;
s = 0;
% Start condition
if ismembc(A(1,1),1:2)
s = 1;
end
for n = 2:numel(A(:,1))-1
if A(n,1) == 0 && ismembc(A(n+1,1),1:2)
if s
c = c+1;
Out{c} = A(s:n,:);
end
s = n+1;
end
end
% End condition
if s < n
Out{c+1} = A(s:end,:);
end
7 Comments
More Answers (1)
Andrei Bobrov
on 16 May 2011
more variant
A = A(:);
I = cumsum([0;diff(A)]~=0 & (A ~= 0));
out = arrayfun(@(x)A(I==x),1:max(I),'un',0);
same with the loop
A = A(:).';
I = cumsum([0,diff(A)]~=0 & (A ~= 0));
out = cell(1,max(I));
for j = 1:max(I),
out{j} = A(j==I);
end
4 Comments
Oleg Komarov
on 16 May 2011
I edited my solution to take into account initial conditions (if A doesn't start with a 0) and to split a matrix on the basis of the first array.
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