Asked by Devia Rafika Putri
on 15 May 2013

this is my program:

v = 120;

r1 = 1.8;

x1 = 2.4;

r2 = 3.5;

x2 = 1.2;

xm = 60;

ns = 1800;

ws = 188.5;

s = (0.5:1:50)/50;

s (1) = 0.0001;

nm = (1-s)*ns;

for i = 1:51;

zf(i) =(((r2/s(i))+(j*x2))*(j*xm))/(((r2/s(i))+(j*x2))+(j*xm));

zb(i) = (((r2/(2-s(i)))+(j*x2))*(j*xm))/(((r2/(2-s(i)))+(j*x2))+(j*xm));

I(i) = v/(r1+(j*x1)+(0.5*zf(i))+(0.5*zb(i)));

PagF(i) = (abs(I(i)^2))*(0.5*real(zf(i)));

PagB(i) = (abs(I(i)^2))*(0.5*real(zb(i)));

Pag(i)=PagF(i)-PagB(i);

Tind(i) = Pag(i)/ws;

end

figure (1);

plot(nm,Tind,'Color','b','LineWidth',2.0);

grid on;

hold off;

*but after i run this program an error occurred with argument: Attempted to access s(51); index out of bounds because numel(s)=50.

Error in ==> fasbel3 at 15 zf(i) =(((r2/s(i))+(j*x2))*(j*xm))/(((r2/s(i))+(j*x2))+(j*xm));

how to fix it? please help thanks.. with sincerity :)

*No products are associated with this question.*

Answer by Andrei Bobrov
on 15 May 2013

Edited by Andrei Bobrov
on 15 May 2013

Accepted answer

v = 120; r1 = 1.8; x1 = 2.4; r2 = 3.5; x2 = 1.2; xm = 60; ns = 1800; ws = 188.5;

s = [.0001;(.5:50).'/50]; s1 = [2-s,s]; z =(r2./s1+1i*x2)*1i*xm./( r2./s1+1i*(x2+xm) ); I = v./(r1+1i*x1+mean(z,2)); Tind = diff(bsxfun(@times,abs(I.^2),real(z)*.5),1,2)/ws;

plot((1-s)*ns,Tind,'Color','b','LineWidth',2.0); grid on;

Devia Rafika Putri
on 15 May 2013

your program is work, thanks so much andrei!!! but there is some code that i dont understand..

s = [.0001;(.5:50).'/50];

s1 = [s, 2-s];

Tind = -diff(bsxfun(@times,abs(I.^2),real(z)*.5),1,2)/ws;

what that means? can you explain?? thanks before..

with sincerity Devia

Andrei Bobrov
on 15 May 2013

Hi Devia!

Please read about functions of the MATLAB: bsxfun, diff.

Rewrite code:

s = [.0001;(.5:50).'/50]; s1 = [2-s,s]; z =(r2./s1+1i*x2)*1i*xm./( r2./s1+1i*(x2+xm) ); I = v./(r1+1i*x1+mean(z,2)); Tind = diff(bsxfun(@times,abs(I.^2),real(z)*.5),1,2)/ws;

as:

s = [.0001;(.5:50).'/50]; s1 = [2-s,s]; z =(r2./s1+1i*x2)*1i*xm./( r2./s1+1i*(x2+xm) ); I = v./(r1+1i*x1+mean(z,2)); Ia2 = abs(I.^2); r = real(z)*.5; P = bsxfun(@times,Ia2,r); % as in your code: P = [PagB PagF]; Pag = diff(P,1,2); % as Pag = PagF - PagB; Tind = Pag/ws;

Devia Rafika Putri
on 15 May 2013

Hi Andrei, thank you so much for your explain.. i'm so grateful.

but actually I have another problem. is about 1 phase motors, can you help me?

if you can, I will send my problem to your email..

thanks so much, Andrei..

with sincerity Devia

Answer by Yao Li
on 15 May 2013

It seems the length of array s is 50, but you wanna call s(51) in the for loop

Show 1 older comment

Devia Rafika Putri
on 15 May 2013

thanks a lot Yao Li.. its work.. are you an electrical engineer? i hv a more problem..

Devia Rafika Putri
on 15 May 2013

lol.. thanks so much Yao li, I've sent an email to you .. if you're not busy please check it..

Opportunities for recent engineering grads.

## 4 Comments

## Craig Cowled (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/75804#comment_149009

Devia,

Your

for _loop has 51 cycles, however, your variable _s _only has 50 elements. There are other problems with your code too. Just change the for loop to _for i = 1:50There is no need for the semicolon at the end of a _for _statement.

Craig.

## Devia Rafika Putri (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/75804#comment_149015

thanks a lot craig.. craig are u an electrical engineer., i hv a more problem..

## Craig Cowled (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/75804#comment_149019

Devia, Andrei's code is much neater. No need for a loop, just use element wise divide './'. And no, I'm not an electrical engineer. I'm a structural engineer working on experimental structural dynamics problems.

## Devia Rafika Putri (view profile)

Direct link to this comment:http://www.mathworks.com/matlabcentral/answers/75804#comment_149023

ok craig.. i see.. but some code from andrei, i still dont understand.. but i'll find it..

ooh, I thought you were an electrical engineer

because I'm having problems with programs relating to single phase motor..

thanks so much craig..you are very helpful..