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How can I create a sparse matrix containing (3,3) block matrices on the main diagonal and on diagonals below and above the main diagonal without using loops?

Asked by Manuel

Manuel

on 19 May 2013
Accepted Answer by Cedric Wannaz

Cedric Wannaz

The idea is to create a (3m,3m) sparse matrix with small (3,3) matrices on the main diagonal and on diagonals below and above the main diagonal. By saying this, I want that each time the main diagonal of the small (3,3) matrix is on the main diagonal or on another diagonal respectively. There is no gap between the small (3,3) matrices on the diagonals. How can I use the functions sparse, spdiags, blkdiag to create this matrix? If there are other functions guaranteeing sparsity that's fine.

2 Comments

Cedric Wannaz

Cedric Wannaz

on 19 May 2013

Did you generate these m 3x3 sparse matrices already or do you want to avoid building them and build directly the block diagonal large sparse matrix? If you have these small matrices already defined, what have you tried so far using BLKDIAG?

Manuel

Manuel

on 20 May 2013

I've got all the 3x3 matrices (they are not sparse) already. Basically they are the local Hessian operator on a manifold. Now I want to store them in this huge sparse matrix to do a Newton step (Newton Method). I've thought of using the Tensor Toolbox since blkdiag doesn't give me a sparse matrix.

Manuel

Manuel

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2 Answers

Answer by Cedric Wannaz

Cedric Wannaz

on 20 May 2013
Accepted answer

BLKDIAG will give you a sparse matrix if one of its inputs is sparse. Try building the 3x3 matrices as sparse, or converting them (or just one) to sparse, before using BLKDIAG; it should work fine.

1 Comment

Manuel

Manuel

on 30 May 2013

Hey Cedric, Thanks a lot for your answer. That's been a great help. Manuel

Cedric Wannaz

Cedric Wannaz

Answer by Iain

Iain

on 20 May 2013

You can initialise a sparse matrix as:

matrix = sparse(zeros(3*m,3*m));

If you then use it as:

matrix(1:3,1:3) = [a b c; d e f; g h i];

matrix(3+1:3,3+1:3) = [j k l; m n o; p q r];

... etc you will get what I think you're asking for.

1 Comment

Manuel

Manuel

on 20 May 2013

Thanks lain for your answer. You got my idea. But my matrix will be huge and with your idea I'll have to use a loop. But loops are way to slow for what I'm doing.

Iain

Iain

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