## Convert xy Coordinates to Matrix

on 26 May 2013

### Andrei Bobrov (view profile)

I have an xy coordinates positions (100x2) and another z vector (100x1) with values corresponding to each xy coordinate. How can I make a matrix of the coordinates with the position of each coordinate having the corresponding z value? Thanks!

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### Andrei Bobrov (view profile)

on 27 May 2013
Edited by Andrei Bobrov

### Andrei Bobrov (view profile)

on 27 May 2013

after John's comment in Image Analyst's answer:

```out = accumarray([x(:),y(:)],z(:),[10 10]);
```

or

```out = zeros(10);
out(sub2ind(size(out),x,y)) = z;
```

John

### John (view profile)

on 27 May 2013

Thanks! it works now :)

Andrei Bobrov

### Andrei Bobrov (view profile)

on 27 May 2013

Hi John! NOTE: Second part my answer (code after 'or') is the same as the Image Analyst' answer...

John

### John (view profile)

on 27 May 2013

Now I get it, thanks for the clarification.

### Image Analyst (view profile)

on 26 May 2013

Try this:

```% Setup / initialization.
% Start out matrix as zeros.
m = zeros(20,10);
% Generate 100 random coordinates.
xy = int32(randi(10, 100, 2));
% Get matrix values for those x,y locations
z = randi(255, 100, 1); % 100 values.
```
```% Now, do what the poster, John, wants to do.
% Assign the z values to the (x,y) coordinates at the corresponding row.
% E.g. m at (x(1), y(1)) will have a value of z(1).
% m at (x(2), y(2)) will have a value of z(2).  And so on.
indexes = sub2ind([20, 10], xy(:,1), xy(:,2))
m(indexes) = z
```

John

### John (view profile)

on 27 May 2013

Thanks for your help, unfortunately it didn't work. Here's my data. x and y are the coordinates and z is the corresponding value for each coordinate.

x [4 7 5 9 3 5 5 2 1 1 ]

y [9 2 9 7 9 9 1 4 7 6 ]

z [1 0 1 1 1 0 1 0 1 0 ]

I wish to create a 10x10 matrix (since my xy coordinates are between 1 and 10). In this matrix, I want each coordinate, say for instance, the first xy coordinate (4,9) whose z value is 1 is shown as 1 in column 4 row 9 of the matrix.

Image Analyst

### Image Analyst (view profile)

on 27 May 2013

Of course it DOES work if you adapt it to a 10 by 10.

```m=zeros(10);
indexes = sub2ind([10, 10], x, y)
m(indexes) = z
```

When I did my example, I picked random numbers for x, y, and z, and random sizes. You were supposed to know that and be able to make the simple adaptations yourself. But anyway, andrei did it for you so you're all set now.

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