While loop for the elements of an array

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I have an array:
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
I want to make a while loop that does the following
enas=0;
while a(i)==1 %
enas=enas+1;
end
But I don't know how to express it in matlab. Can you help me please?
  1 Comment
Image Analyst
Image Analyst on 27 May 2013
It's recommended not to use i (the imaginary variable) as a variable name.

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Accepted Answer

Image Analyst
Image Analyst on 27 May 2013
Here's how you'd do it:
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
enas=0;
k = 1;
while a(k)==1 %
enas=enas+1
k = k + 1
end
But here's how a real MATLAB programmer would do it:
enas = find(a~=1, 1, 'first')-1
  3 Comments
Image Analyst
Image Analyst on 27 May 2013
If you need to count the length of each stretch of 1's in your array, and if you have the Image Processing Toolbox, you'd do this:
measurements = regionprops(a==1, 'Area');
allLengths = [measurements.Area]; % Get lengths of all stretches of 1s.
If you don't have the Image Processing Toolbox, it's more difficult - let me know if you have that unfortunate case.
Giorgos Papakonstantinou
Giorgos Papakonstantinou on 27 May 2013
Unfortunately I don't. I just do:
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
enas = find(a~=1)-1
segments=zeros(length(enas),1);
segments(1,1)=enas(1);
segments(2:end,1)=diff(enas)-1;
segments
which a bit complicated but it does the job... If you have better ideas tell me. thank you!

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More Answers (1)

Jason Nicholson
Jason Nicholson on 27 May 2013
See the lines below. This will work.
a=[1 1 1 1 1 1 1 10 1 1 1 1 1 1 12 1 1 1 1 3];
i = 1;
enas=0;
while a(i)==1 %
enas=enas+1;
i = i +1;
end
  4 Comments
Matt Kindig
Matt Kindig on 27 May 2013
Edited: Matt Kindig on 27 May 2013
This should do it:
b = [0, a, 0]; %ensure that ends are not 1
edges = find(b~=1); %location elements that are not 1
spans = diff(edges)-1; %distance between edges is span of 1's
enas = spans(spans~=0) %should output 7 6 4
Giorgos Papakonstantinou
Giorgos Papakonstantinou on 28 May 2013
Suppose that I want find the edges of ones and of not ones. Suppose the array is:
a=[1 1 1 1 1 1 12 10 1 1 1 1 1 11 12 1 1 1 2 3]
a(1:6) -->area1 of ones
a(7:8) -->area1 of not ones
a(9:a13) -->area2 of ones
a(14:15)-->area2 of not ones
a(16:19)-->area3 of ones
a(20) -->area3 of not ones
and so on..

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