## Find Maximum one of numerical arguments

on 27 May 2013

### Image Analyst (view profile)

How can i find max of 30 arguments max(H1,H2.....H30)

But error message occured "Error using max Too many input arguments.MAX with two matrices to compare and a working dimension is not supported"

Is there any other way?

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### Image Analyst (view profile)

on 27 May 2013
Edited by Image Analyst

### Image Analyst (view profile)

on 27 May 2013

Put brackets around them to make them a single array, as my answer below shows.

Try this:

```[maxValue, indexAtMaxValue] = max([H1, H2, H3, H4, ...ETC...... , H29, H30]);
```

Light

### Light (view profile)

on 27 May 2013

[maxValue, indexAtMaxValue]=max([H01,H12,H23,H14,H45,H56,H47,H77,H78,H89,H910,H811,H1112,H1113,H1314,H1315,H1516,H1617,H1618,H1819,H1520,H2021,H2022,H2223,H2224,H2425,H2426,H2627,H2628,H2829]);

Result:

maxValue =

`     0`

indexAtMaxValue =

`     1`

H values less than 0.01.... What will i do

Image Analyst

### Image Analyst (view profile)

on 27 May 2013

Once again: You forgot to give us the values for the H's, so we can't try my answer.

To drive the point home: How on earth am I supposed to know what value H01 takes on? Or what value any of the other variables have? The answer is I don't. Unless you supply them to me. GIVE ME CODE THAT SAYS:

```H01 = 0.003342243423;  % or whatever.
...
H2022 = 0.233423423423; % or whatever.
and so on, for all the H's.
```
Light

### Light (view profile)

on 28 May 2013

So sorry!! My CODE is almost 500 rows and all of it relative and it is changed in next iterations .......

Anyway!!! Thanks for your big help :-))))

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