Asked by hdr mhr
on 1 Jun 2013

I have a vector that consists of some numbers in the following way: A = [153 244 253 353 453 530 653 ...] The pattern is that there is always 153,253,353,...,2353 (these represent time i.e. 1:53am,...11:53pm) for a day. In between these *53 numbers there are some numbers that I don't wish to keep them. For example between 353 and 453, a 433 appears which needs to be removed from the vector. So the final result I wish to get is vector A = [153 253 353 ...2353] (of course in the original vector I have, this pattern for one day is repeated for a whole year).

Any thought on how to do this?

I would really appreciate any answer.

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Answer by the cyclist
on 1 Jun 2013

Edited by the cyclist
on 1 Jun 2013

Accepted answer

First, try to define an index that identifies the values you don't want. It sounds like this will do it:

idx = not((mod(A,100)==53));

Then, you can use that index to remove the unwanted values:

A(idx) = [];

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hdr mhr
on 5 Jun 2013

Now that I ran the program, I realized that some of the "53" ones are missing (for some days). So the array I have is something like this:
A = [53 153 253...2353 53 153...2353 153 ` 353`...2353], which a "253" is missing between 153 and 353 in that particular day. I would like to insert a specific number, say 10000 whenever there is a missing "*53", so that I can locate the missing ones. Can you think of an efficient way to do this?

Thank you

the cyclist
on 5 Jun 2013

Answer by davood fouladi
on 23 Aug 2014

For example,5 elements are removed from x=1:10 x(5)=[] Now what should I be removed for a number of

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