Now i combined answers. Help me about this iteration. I want it iterate until whole matrix zero.
if ~sum(A(:)) % this iteration will be continued until whole matrix zero 0
f = find(any(A==-1,2)); % i have to find row which including only one -1, if found 2 or more, i have to pick just one of them in that iteration. How can i find it?
% in one column only one -1 and 1. then after find row with only one -1, i have to add it to the row with 1 which is staying with one column. It is the way my matrix will be zero.
2nd row which including only one -1 is added to the first row. after that:
If all whole matrix not zero. then will be iterated again. Please give me some clue. Help me!
Thank you for ADVICE!
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while true if (the ending condition is met) break end rownum = index of one row that has exactly one -1 neg1idx = column index of -1 in row number rownum plus1rownum = row index of row that has +1 in column number negidx A(plus1rownum,:) = A(plus1rownum,:) + A(rownum, :); end
It is, however, highly recommended that you add protections in case the input matrix is not structured the way you expect.
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