Why fopen does not accept the path when it is assigned to a variable.
1 view (last 30 days)
Show older comments
filename=['tests/testbkc/result-1/abc.txt']; fid=fopen('filename','w')
Here fid returns bigger than 3 but it does not create any file.
If I wrote the path directly into fopen then everything is okey. But I need to use variable.
what should be the type of filename? Isnt it char?
Does anybody have an idea? Thanks
0 Comments
Accepted Answer
Ahmed
on 7 Jun 2013
omit the the '' to get the content of the variable filename.
fid=fopen(filename,'w')
0 Comments
More Answers (0)
See Also
Categories
Find more on Low-Level File I/O in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!