Discover MakerZone

MATLAB and Simulink resources for Arduino, LEGO, and Raspberry Pi

Learn more

Discover what MATLAB® can do for your career.

Opportunities for recent engineering grads.

Apply Today

Finding numbers over a value in a matrix/array

Asked by Brian on 14 Jun 2013

Hi, I have a 365x10 matrix/array? not sure what it would be called need to find the amount of numbers in a certain range/below a certain value eg 0.

Thanks for any help.

0 Comments

Brian

Products

No products are associated with this question.

3 Answers

Answer by Image Analyst on 14 Jun 2013
Edited by Image Analyst on 14 Jun 2013
Accepted answer

Try this:

T = rand(365,10);  % Some random data
% Define the range as [0, 0.2].
rangesLowValue = 0;
rangesHighValue = 0.2;
% Count the number of values in the range:
countLessThanPoint3 = sum(T(:) >= rangesLowValue & T(:)<rangesHighValue)

3 Comments

Brian on 14 Jun 2013

Thanks, I'm really not getting this though.

I have a pre-defined matrix of real data, this is what I wrote:

load('temp.mat')
disp(T);
ranges High Value = 0
count Less than point3=sum(T(:) <= ranges High Value

but I'm doing something wrong clearly ...

Image Analyst on 14 Jun 2013

Yes. You can't write variable names with spaces in them. Plus I don't know why you didn't just do it like I said. Explain what this means " in a certain range/below a certain value eg 0." Do you mean that the limits of the entire range (both the low and high values) are less than 0? Like the low value = -999 and the high value is -1?

Brian on 15 Jun 2013

\Thanks a lot..I'm really new to matlab as you may have noticed.

Image Analyst
Answer by Andrei Bobrov on 14 Jun 2013
A = rand(20,10); 
A(A < .3) = -A(A < .3); % your array
out = nnz(A < 0);

1 Comment

Brian on 14 Jun 2013

Hi thanks,

when I use the following I get the answer for the first part, the numbers less than 0, but I'm doing something wrong in the second, it says '??? Index exceeds matrix dimensions.' what do I do?

Andrei Bobrov
Answer by Azzi Abdelmalek on 14 Jun 2013
range=2
idx=find(abs(yourarray)<range)

0 Comments

Azzi Abdelmalek

Contact us