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findobj for multiple 'Tag's

Asked by Vincent I on 17 Jun 2013

Hi, is there any way I could look for multiple tags like this:

 findobj(0,'Tag',['Name1','Name2','Name3',etc])

instead of

 findobj(0,'Tag','Name1','-or','Tag','Name2','-or','Tag','Name3'...etc)

????

Thank you

0 Comments

Vincent I

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2 Answers

Answer by Andrew on 17 Jun 2013
Edited by Andrew on 17 Jun 2013
Accepted answer

When you use findobj, it returns the object handle (May look like an arbitrary number to the user). There are many ways to do what you want I think. Here is one

First, create a cell array with the names of the tags you want to find, then use findobj in a loop to collect the object handles.

mytags = {'Name1' 'Name2' 'Name3' ... )
for i = length(mytags)
     objecthandles.(genvarname(mytags{1})= findobj(0, 'tag', mytags{1})
end

The output should be a structure of variables called 'objecthandles' that has variables for each of your tag names, and the variables store the object handles.

The output should look something like:

objecthandles = 
   objecthandles.Name1 = 300.12
   objecthandles.Name2 = 292.73
   objecthandles.Name3 = 512.42
   ...

You now are able to call all of their handles at will. Let me know if I made a syntax error or soemthing and I can correct this.

1 Comment

Vincent I on 18 Jun 2013

i was trying to limit using a loop to get the handle for each figure but i guess this is the only way to go. thanks for your answers

Andrew
Answer by per isakson on 17 Jun 2013
Edited by per isakson on 17 Jun 2013

A shot in the dark with R2012a. This returns handles rather than an error message

    >> findobj(0,'Tag',{'Name1','Name2','Name3'} )
    ans =
             0
      221.0011
      220.0011
      219.0011
      218.0011
      188.0011
      156.0011
      190.0011
      189.0011
      158.0011
      157.0011
    >> 

Cell array would be the Matlab way. Compare set. However, I don't think it is covered by the documentation.

No good:

    >> h = findobj(0,'Tag',{'Name1','Name2','Name3'} );
    >> get( h, 'Tag' )
    ans = 
        ''
        ''
        ''
        ''
        ''
        ''
        ''
        ''
        ''
        ''
        ''

2 Comments

Andrew on 17 Jun 2013

Nice! I think my answer was doing it the hard way.

Always better to use arrays/vectors than a loop whenever possible. It is much more resource efficient. Use this answer Victor

per isakson on 17 Jun 2013

I'll file this as a request or bug:-)

per isakson

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