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## Count the "areas" of zeros and the "areas" of ones in a vector?

Asked by Giorgos Papakonstantinou

### Giorgos Papakonstantinou (view profile)

on 21 Jun 2013
Accepted Answer by Andrei Bobrov

### Andrei Bobrov (view profile)

I have a vector:

```a=[0 1 1 1 1 1 1 0 0 1 1 1 1 1 0 0 1 1 1 0 1 ];
```

in which I would like to count the "areas" of zeros and the "areas" of ones. In the example above I have

4 areas of zeros and 4 areas of ones. Thank you!

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## 3 Answers

### Andrei Bobrov (view profile)

Answer by Andrei Bobrov

### Andrei Bobrov (view profile)

on 21 Jun 2013
Accepted answer
```a=[0 1 1 1 1 1 1 0 0 1 1 1 1 1 0 0 1 1 1 0 1 ];
```
```lc = [true;diff(a(:))~=0];
```
```x = a(lc);
```
```zerosareas = sum(~x);
onesareas = sum(x);
```

#### 1 Comment

Giorgos Papakonstantinou

on 21 Jun 2013

Thank you Andrei

### Jan Simon (view profile)

Answer by Jan Simon

### Jan Simon (view profile)

on 21 Jun 2013

Another approach which might be faster for large data sets: FEX: RunLength:

```a = [0 1 1 1 1 1 1 0 0 1 1 1 1 1 0 0 1 1 1 0 1 ];
b = RunLength(a);
nZero = sum(b == 0);
nOne  = length(b) - nZero;  % Or: sum(b == 1)
```

#### 2 Comments

Giorgos Papakonstantinou

on 22 Jun 2013

Thank you Jan!

Jan Simon

### Jan Simon (view profile)

on 22 Jun 2013

For 100'000 elements, the RunLength approach is twice as fast as the DIFF method. But as long as both methods need only some milliseconds, this might not really matter.

### Image Analyst (view profile)

Answer by Image Analyst

### Image Analyst (view profile)

on 23 Jun 2013

I know you already accepted an answer, but if you have the Image Processing Toolbox there is a straightforward one-liner solution to get either of those numbers:

```a=[0 1 1 1 1 1 1 0 0 1 1 1 1 1 0 0 1 1 1 0 1];
[~, numberOf1Regions] = bwlabel(a)      % Get # of "1" regions.
[~, numberOf0Regions] = bwlabel(~a)     % Get # of "0" regions.
```

#### 0 Comments

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