## Need half of my contour plot

### Maryam (view profile)

on 18 Jul 2013
Accepted Answer by Kye Taylor

### Kye Taylor (view profile)

Hello I have a contour of the pressures over a surface. Basically, I had vectors x and y which were locations on the surface and on each location, I had a value for pressure. I have a rectangular plot. I was wondering if there is a way to split my plot from the diagonal and show just the results for either upper or lower triangles?

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### Kye Taylor (view profile)

Answer by Kye Taylor

### Kye Taylor (view profile)

on 18 Jul 2013
Edited by Kye Taylor

### Kye Taylor (view profile)

on 18 Jul 2013

Check out the tril and triu functions. For example if you have data similar to

```[x,y]= meshgrid(-1:.05:1);
z = x.^2+y.^2;
contour(x,y,z)
```

Try something like

```zLowerTri = tril(z);
contour(x,y,zLowerTri)
```

Since contour plots with the origin at lower left instead of upper right, you may prefer either

```zLowerTri = tril(z);
contour(x,y,zLowerTri)
axis ij
```

or

```contour(x,y,fliplr(tril(fliplr(z))))
```

Maryam

### Maryam (view profile)

on 18 Jul 2013

I used "contour(x,y,fliplr(tril(fliplr(z))))" and I got what I wanted. Thank you very much. I now need to Also, to show the deleted parts in white? Is there any way to do that? In the deleted area, my contour is all red which corresponds to the value=0 in my color map.

### Pourya Alinezhad (view profile)

on 19 Jul 2013

use "nan" as i mentioned below to make that part invisible... functions you use {ex:tril(z)} replace the data values with zero,which itself could be a data!!!

Maryam

### Maryam (view profile)

on 19 Jul 2013

Thank you very much. I now have what I wanted.

### Pourya Alinezhad (view profile)

on 18 Jul 2013
Edited by Pourya Alinezhad

### Pourya Alinezhad (view profile)

on 18 Jul 2013

hello maryam, run following lines of code.

```x=0:0.1:10;
y=x;
j=1;
z=meshgrid(x,y);
h=ones(length(x),length(x))*nan;
for i=1:length(x)
for j=1:length(y)
if i>j
h(i,j)=z(i,j);
end
end
end
surf(sin(h)./sqrt(h))
figure
contourf(sin(h)./sqrt(h))
```

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