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Asked by Diego on 19 Aug 2013

Hello,

Im having trouble fixing the "cannot be classified error" in my parfor loop:

n = 1; post = zeros(100,100,100) wvals = 0:.01:1; numerator = zeros(length(post(:,:,n))); currW = cell(length(wvals), length(wvals)); parfor indeX = 1:length(wvals) for indeY = 1:length(wvals) if n == 1 prior = ones(length(wvals), length(wvals)); % initially uniform prior currW{indeX, indeY} = [wvals(indeX) wvals(indeY)]'; else prior = posterior(:,:,n-1); % previous posterior prevY = yChanOutput(n-1); % W_t(u) = S_{y-1}(W_{t-1}(u)) currW{indeX, indeY} = map(prevW{indeX, indeY}, S_opt{prevY+1}, wvals, resolution); end

currX = encode(currW{indeX, indeY}); numerator(indeX, indeY) = prior(indeX, indeY)*likelihood(currChanOutputY, currX, errorProb); end end

posterior(:,:,n) = numerator/(sum(numerator(:)*(1/resolution))); %/( sum(numerator*(1/resolution)) );

prevW = currW;

There is an outer loop that is not shown, that handles moving n around. I get an error saying currW cannot be classified, though it looks like a "sliced output" variable. Any help would be great thanks!

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Answer by Walter Roberson on 20 Aug 2013

It is not clear at the moment that currW{indeX, indeY} is ever used outside the parfor(). If it is not, then use an unindexed name (writing over it each time.)

If you do need currW after the parfor() then try constructing a local cell array currY inside the parfor, and at the end of the loop store that in a cell vector indexed by indeX. If you need to you can break it out from a vector of vectors to a 2D array after the parfor.

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Diego on 21 Aug 2013

Im confused, I change prev and currW to be

How do I initialize currW to be indexed like that? And the error was complaining about currW

Walter Roberson on 21 Aug 2013

Here is a partial conversion. I suspect it would be a bit more efficient. See my comments below the code:

n = 1; post = zeros(100,100,100) wvals = 0:.01:1; Nw = length(wvals); numerator = zeros(length(post(:,:,n))); currW = cell(Nw, 1); parfor indeX = 1:Nw currWX = cells(Nw,1); prevWX = prevW{indeX}; for indeY = 1:Nw if n == 1 prior = ones(Nw, Nw); % initially uniform prior currWX{indeY} = [wvals(indeX) wvals(indeY)]'; else prior = posterior(:,:,n-1); % previous posterior prevY = yChanOutput(n-1); % W_t(u) = S_{y-1}(W_{t-1}(u)) currWX{indeY} = map(prevWX{indeY}, S_opt{prevY+1}, wvals, resolution); end

currX = encode(currWX{indeY}); numerator(indeX, indeY) = prior(indeX, indeY)*likelihood(currChanOutputY, currX, errorProb); end currW{indeX} = currWX; end

posterior(:,:,n) = numerator/(sum(numerator(:)*(1/resolution))); %/( sum(numerator*(1/resolution)) );

prevW = currW;

I fixed the indentation, which was important for understanding that the prevW is not to be updated until after the parfor loop completes. You do not initialize prevW outside the loop, so the assumption I must make is that n is not *always* set to 1, but it will be set to 1 the first time this code is executed. I probably would have programmed this slightly differently, with a completely different code path for n==1 or not, as it is a waste of time to keep testing n for each indeX and indeY combination.

Diego on 21 Aug 2013

Hello! Thank you for your help. It is very interesting to see what you cleverly did with cells! I have incorporated your changes and I get it to run for n=1. However, when the outer loop moves n=2, I get the following error:

Error using parallel_function (line 589)

Cell contents reference from a non-cell array object.

Error stack: myFunction>(parfor body) at 134

Error in myFunction(line 123) parfor indeX = 1:lenWvals

Line 134 is:

currWX{indeY} = map(prevWX{indeY}, S_opt{prevY+1}, wvals, resolution);

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