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Asked by hdg D
on 21 Aug 2013

Hi I have a structure that looks like the below

a = mydata:[135x6] myid:{1x6} mydates = [135x1]

I would like to separate out data into positive and negative I would go through each column in mydata and filter for positive and negative and match it to the corresponding dates

so that in the end i have 6 structures

so for example

apos(1) = mydata:[120x1] mydates:[120x1] myid ={1}

is there a clean way to do this rather than using a for loop?

Thanks, HD

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Answer by Walter Roberson
on 21 Aug 2013

Edited by Walter Roberson
on 21 Aug 2013

Accepted answer

aneg = cell2mat( arrayfun( @(K) struct( 'mydata', a.mydata(a.mydata(:,K) < 0,K), 'mydates', a.mydates(a.mydata(:,K) < 0), 'myid', a.myid(K)), 1:size(a.mydata,2),'Uniform', 0) ); apos = cell2mat( arrayfun( @(K) struct( 'mydata', a.mydata(a.mydata(:,K) > 0,K), 'mydates', a.mydates(a.mydata(:,K) > 0), 'myid', a.myid(K)), 1:size(a.mydata,2),'Uniform', 0) );

Question: what if the data is exactly 0?

hdg D
on 21 Aug 2013

Thanks for your help but is this syntax correct the 1:size(a.mydata(2),'Uniform', 0)

The 0 will be clubbed in with thepositive

Walter Roberson
on 21 Aug 2013

Sorry, I fixed my typo.

If you want 0 to be included with positive, then use >= 0 instead of > 0 for apos

Answer by Azzi Abdelmalek
on 21 Aug 2013

Edited by Azzi Abdelmalek
on 21 Aug 2013

%Example a.mydata=randi([-10 10],135,6) a.myid=randi([-10 10],1,6) a.mydates =randi([-10 10],135,1) %-------------------------------- c1=a.mydata(:); c2=a.myid(:); c3=a.mydates(:); apos.mydata=c1(c1>=0) apos.myid=c2(c2>=0) apos.mydates=c3(c3>=0)

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