How to replace an element in an struct array

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Hi,
I have a problem about replacing an element in the array with a new one.
Could you please take a look and tell me what i'm doing wrong?
breedpop =
1x100 struct array with fields:
sched
harvvol
npv
penalty
fitness
% every array has 10 element in it.
I tried to replace one of the element in the breedpop.penalty array(doesnt matter index of the element) this way
breedpop(i).penalty = newgeneration(i).penalty;
It works if i run once but when i run it more than 100(number of iteration) bredpop.penalty becomes more than 10 element.
How can I do it?
  1 Comment
Walter Roberson
Walter Roberson on 21 Aug 2013
We would need to see more about how you create newgeneration(i).penalty

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Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 21 Aug 2013
Edited: Azzi Abdelmalek on 21 Aug 2013
Because newgeneration(i).penalty when i >100 contains more then 10 elements
If you want to take the first 10 elements
breedpop(i).penalty(1:10) = newgeneration(i).penalty(1:10);
  2 Comments
tevzia
tevzia on 21 Aug 2013
I wanna replace one from the list(newpopulation.penalty) to old list (breedpop.penalty)
breedpop(i).penalty = newgeneration(i).penalty(end)
however it didn't work
tevzia
tevzia on 21 Aug 2013
I solve it. thank you
breedpop(n).penalty = newpopulation(i).penalty(end)
n is the last one of the list (number of the elements)

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