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How to replace an element in an struct array

Asked by tevzia

tevzia

on 21 Aug 2013
Accepted Answer by Azzi Abdelmalek

Azzi Abdelmalek

Hi,

I have a problem about replacing an element in the array with a new one.

Could you please take a look and tell me what i'm doing wrong?

 breedpop = 
1x100 struct array with fields:
    sched
    harvvol
    npv
    penalty
    fitness
    % every array has 10 element in it.

I tried to replace one of the element in the breedpop.penalty array(doesnt matter index of the element) this way

breedpop(i).penalty = newgeneration(i).penalty;

It works if i run once but when i run it more than 100(number of iteration) bredpop.penalty becomes more than 10 element.

How can I do it?

1 Comment

Walter Roberson

Walter Roberson

on 21 Aug 2013

We would need to see more about how you create newgeneration(i).penalty

tevzia

tevzia

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1 Answer

Answer by Azzi Abdelmalek

Azzi Abdelmalek

on 21 Aug 2013
Edited by Azzi Abdelmalek

Azzi Abdelmalek

on 21 Aug 2013
Accepted answer

Because newgeneration(i).penalty when i >100 contains more then 10 elements

If you want to take the first 10 elements

breedpop(i).penalty(1:10) = newgeneration(i).penalty(1:10);

2 Comments

tevzia

tevzia

on 21 Aug 2013

I wanna replace one from the list(newpopulation.penalty) to old list (breedpop.penalty)

breedpop(i).penalty = newgeneration(i).penalty(end) 

however it didn't work

tevzia

tevzia

on 21 Aug 2013

I solve it. thank you

breedpop(n).penalty = newpopulation(i).penalty(end)

n is the last one of the list (number of the elements)

Azzi Abdelmalek

Azzi Abdelmalek

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