How to take the z transform of a delayed unit step using ztrans?
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To simplify what I want to do say I need to take the z transform of a delayed unit step. In my professors notes the following was done for the unit step:
syms k
ek=1^k;
Ez=ztrans(ek)
Ez =
z/(z - 1)
The result is what is expected. So how would you define ek for a delayed unit step? For example let's say I want the z transform of u(k-2).
Thanks!
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Answers (1)
Azzi Abdelmalek
on 5 Sep 2013
Edited: Azzi Abdelmalek
on 5 Sep 2013
%heavyside(0)=1/2 not 1
It's like you have step(k)+0.5*kronecker(k) then it's z transform will be
z/(z-1)+1/2
3 Comments
Azzi Abdelmalek
on 8 Nov 2014
Asia Khan commented
I have the same query?? How to take the z transform of a delayed unit step using ztrans???? please tell me??
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