How to take the z transform of a delayed unit step using ztrans?

To simplify what I want to do say I need to take the z transform of a delayed unit step. In my professors notes the following was done for the unit step:

syms k

ek=1^k;

Ez=ztrans(ek)

Ez =

z/(z - 1)

The result is what is expected. So how would you define ek for a delayed unit step? For example let's say I want the z transform of u(k-2).

Thanks!

Answer 1

[Azzi Abdelmalek]

%heavyside(0)=1/2 not 1

It's like you have step(k)+0.5*kronecker(k) then it's z transform will be

z/(z-1)+1/2

[Ricker Snow]

Thanks for clearing up the heaviside function. I still don't know how to take the z transform of a delayed unit step though. I will revise my question

[Azzi Abdelmalek]

1^k is not a step function, it's constant

[Azzi Abdelmalek]

Asia Khan commented

I have the same query?? How to take the z transform of a delayed unit step using ztrans???? please tell me??