peak additions /array addition

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I have some code calculating each individual peaks, how can i store them into a large array according to X axis and add them up if they are overlapped.so i should get something like the plot ,
For small range of vt, it will work when I use vt = 5323:stp:5330;
but it wont work if the range is big, say vt=5000:6000. Thanks,
My code:
DT = [1 1 5323.951020 9.682E-22 1.867E+00 .09040 .454
1 1 5327.295500 4.680E-23 2.287E+00 .07510 .301
1 1 5327.390350 1.819E-20 9.299E+00 .10290 .443
1 1 5327.648670 5.002E-23 7.875E-02 .09590 .439
1 1 5327.678120 8.068E-23 5.441E-02 .09320 .429
1 2 5327.964260 1.694E-23 3.105E+00 .09720 .474
1 1 5328.113150 5.769E-23 5.578E-02 .08630 .420
1 1 5329.995810 4.922E-22 1.668E-01 .07400 .460
1 1 5330.470210 3.135E-23 3.254E-02 .09880 .510]; % test data
T = 266;
P = 0.95;
stp = P/100;
a = 1/2.5;
Vgt = 0;
gD(k) = 1.23E-4*sqrt(T/22);
gL(k) = 0.1*P;
for k =1:1:length(DT(:,1))
% % %%% calcualte each peak with 401 pts
vt = DT(k,3)-200*stp:stp:DT(k,3)+ 200*stp;
x=3*(vt-DT(k,3))/gD(k);
y =3*gL(k)/gD(k);
sigma1=0;
sigma2=0;
sigma3=0;
for n = 1:1:20000
sigma1 = sigma1 + 1/(a^2*n^2 + y^2).* exp(-(a^2*n^2 + x.^2));
sigma2 = sigma2 + 1/(a^2*n^2 + y^2).* exp(-(a*n + x).^2);
sigma3 = sigma3 + 1/(a^2*n^2 + y^2).* exp(-(a*n - x).^2);
end
Vgt = exp(-x.^2).*erfcx(y).*cos(2*x.*y)+...
2*a*x.*sin(x.*y)/pi.*exp(-x.^2).*sin(x*y)/(x*y)+...
2*a/pi.*(-y.*cos(2*x.*y).*sigma1 + y/2.*sigma2 +y/2.*sigma3);
hold on;
plot(vt,Vgt,'.-b')
end
  2 Comments
Chong Tao
Chong Tao on 7 Sep 2013
Edited: Chong Tao on 7 Sep 2013
this is what i want to get.
Chong Tao
Chong Tao on 7 Sep 2013
any suggestions? thanks

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Accepted Answer

Image Analyst
Image Analyst on 8 Sep 2013
We don't understand what you're asking. To add arrays, just use the "+" operation:
sumArray = array1 + array2 + array3;
  2 Comments
Chong Tao
Chong Tao on 8 Sep 2013
Edited: Chong Tao on 8 Sep 2013
Thanks, The X coordinates( vt in the code) for each peak are different. how do I line them up according to the vt values and sum them up if there is overlap. So I should get something like above figure. Could you run my code? it will only generate individual peaks
Image Analyst
Image Analyst on 8 Sep 2013
I didn't run your code. If your peaks show up at different indexes, then you're going to have to make a "canvass" long enough to fit them all (basically three times the length of the single array), then place the array so that the peak occurs at the desired index. For example, let's say that your signals are 100 long and your peak could occur anywhere within that 100 elements. So you make a canvass 300 long. This could take a signal that had a peak at the last element (by placing it at element 101 of the canvass), or take a signal that had a peak at element 1 (by placing it at element 200). But you specify where you want all the peaks to be centered. So let's say you want the peaks to be in the middle, at index 150. Now let's say your signal had a peak at element 60, so you need that 60 to happen at 150 of the canvass. So you need to add (150-60) to every element.
theShift = 150-60;
canvass(theShift:theShift+99) = canvass(theShift:theShift+99) + yourSignal;

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More Answers (1)

Chong Tao
Chong Tao on 9 Sep 2013
Thanks a lot Imagine Analyst. That's very helpful.

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