Average value of range of vector elements
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I have a huge amount of data with time stamps concerning temperature and displacement of a bridge deck.
I want to look at hourly intervals and have therefore assigned all the time stamps to their corresponding hour starting from a specific point in time, namely 1/1-2013 00:00.
To clarify:
- from 1/1-2013 00:00 to 1/1-2013 00:59 => hour number 0
- from 1/1-2013 01:00 to 1/1-2013 01:59 => hour number 1
- ...
- from 1/1-2013 07:00 to 1/1-2013 07:59 => hour number 7
This means that my data vectors now look like this:
if true (this is the only way I could find to make the following in vector form)
end
Time[h] Temperature[deg C] Displacement[cm]
0 5.45 0.133
0 5.57 0.136
0 5.68 0.140
1 6.02 0.145
1 6.24 0.147
2 6.56 0.149
2 6.78 0.152
2 6.76 0.152
2 6.80 0.153
... .... .....
Since I want to plot the relationship between temperature and displacement with hourly time steps, I would like to compute the mean value of every hour. This should go into a new vector containing only the hourly averaged time stamps.
My problem is that every hour has a different amount of data points, e.g. hour 0 has three, hour 1 has two and hour 2 has four. How do I go about this without making loops? I imagine that a vectorized method would save a lot of running time compared to loops.
The result I want should look something like the following:
if true (this is the only way I could find to make the following in vector form)
end
Time[h] Temperature[deg C] Displacement[cm]
0 5.57 0.136
1 6.13 0.146
2 6.73 0.152
... .... .....
I hope that I made the problem clear, otherwise I would be happy to elaborate.
Thanks in advance.
Tim
2 Comments
Jan
on 19 Sep 2013
Your tables are nice. For suggesting a solution, it would be helpful, if you explain in which format your data are available. Is this a struct, cell array, 3 different vectors?
Accepted Answer
Jan
on 19 Sep 2013
Edited: Jan
on 19 Sep 2013
avgTemperature = accumarray(Time + 1, Temperature, [], @mean);
Unfortunately I have severe problems to understand the documentation of this command. Because I do not have access to Matlab currently, I can only guess, if the shown method is working.
[EDITED] Although accumarray allows a very compact solution, here a simple FOR loop:
Time1 = Time + 1; % No zeros as indices
n = length(Time1);
maxTime = max(Time1);
accum = zeros(1, maxTime);
len = zeros(1, maxTime);
for k = 1:n
index = Time1(k);
accum(index) = accum(index) + Temperature(k);
len(index) = len(index) + 1;
end
result = accum ./ len;
(Not tested, typos might exist)
6 Comments
Andrei Bobrov
on 19 Sep 2013
z = [0 5.45 0.133
0 5.57 0.136
0 5.68 0.140
1 6.02 0.145
1 6.24 0.147
2 6.56 0.149
2 6.78 0.152
2 6.76 0.152
2 6.80 0.153]
[ii jj] = ndgrid(z(:,1)+1,1:size(z,2)-1)
z23 = z(:,2:end)
out = [unique(z(:,1)),accumarray([ii(:),jj(:)],z23(:),[],@mean)
More Answers (1)
Image Analyst
on 19 Sep 2013
I remember this was answered before, maybe a year ago or so. I don't remember anything to search about it. On the other hand, this is fairly easy with the Image Processing Toolbox. The time is your "labels" and you just call regionprops() on each column to get the values of each label (time). Then sum up and divide by the number in each label. Do you have the Image Processing Toolbox?
3 Comments
Image Analyst
on 19 Sep 2013
Type "ver" on the command line to see what toolboxes are installed. Code using regionprops would go something like (untested):
measurements = regionprops(times, temperatures, 'Area', 'EulerNumber');
meanTempValues = [measurements.Area] ./ [measurements.EulerNumber];
The times and temperatures are assumed to already be extracted into 1D row or column vectors:
times = array2D(:,1);
temperatures = array2D(:, 2);
displacements = array2D(:, 3);
so do that first if you need to. Similarly, call regionprops() again to get the mean displacements over the hours.
measurements = regionprops(times, displacements, 'Area', 'EulerNumber');
meanDispValues = [measurements.Area] ./ [measurements.EulerNumber];
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