Asked by Jenny
on 26 Sep 2013

I have a 84761 x 8 matrix (see attached file as an example of data from the matrix).

I would like to extract all of the rows of data where the month (3rd column) = 11, 12, 1, 2 and 3.

I have set the 'months' to look for in an array called WinterMonths.

I am trying to loop through the matrix (EditedWindTempMatrix) and write all of the data where the month = a 'winter' month to a new matrix.

The 'for loop' loops through the 5 'winter' months.

My problem lies in coding the if loop. i.e. extract the data and write it to a new matrix if the condition is true.

How do I index the new matrix (called WinterWTMatrix) to write the data from the matrix with all the data (EditedWindTempMatrix) to the new matrix only when the condition specified is true?

WinterMonths = [11 12 1 2 3]; % 1 x 5 array

for k = 1:length(WinterMonths); MonthIdx=WinterMonths(k); if EditedWindTempMatrix(:,3)==MonthIdx; WinterWTMatrix=EditedWindTempMatrixdata;

end end

I know that I am not correctly extracting the data from the EditedWindTempMatrix and not correctly writing it to the WinterWTMatrix but I am not sure how to do this.

(I can do it column by column but wanted a more efficient way to extract the desired data).

*No products are associated with this question.*

Answer by Image Analyst
on 26 Sep 2013

Edited by Image Analyst
on 26 Sep 2013

Accepted answer

Jenny:

Use ismember:

% Create sample data: %EditedWindTempMatrix = randi(12, 10,3) % Define which months are winter. WinterMonths = [11 12 1 2 3]; % 1 x 5 array

% Find out which rows are winter. rowsToExtract = ismember(EditedWindTempMatrix(:, 3), WinterMonths) % Get those rows from the original matrix WinterData = EditedWindTempMatrix(rowsToExtract,:)

Jenny
on 30 Sep 2013

Thank you for this. It makes it look easy. Jenny

Answer by Simon
on 26 Sep 2013

Edited by Simon
on 26 Sep 2013

Hi!

Search the third column for your desired month

irows = (EditedWindTempMatrix(:,3) == 11) | ... (EditedWindTempMatrix(:,3) == 12) | ... (EditedWindTempMatrix(:,3) == 1) | ... (EditedWindTempMatrix(:,3) == 2) | ... (EditedWindTempMatrix(:,3) == 3);

Then "irows" is a logical array of length of size(1) of EditedWindTempMatrix. Then

WinterWTMatrix = EditedWindTempMatrix(irows, :);

Image Analyst
on 26 Sep 2013

I think you want OR | instead of AND |.

Simon
on 26 Sep 2013

Yes, 'or' ('|') instead of 'and' ('&'). You're right. I corrected it above.

Your solution looks better than mine. But I experience with "ismember" a slower execution, especially if I use it with full 2d arrays and not with just a column like in this example. But that's another problem.

Jenny
on 30 Sep 2013

Thank you for your help. Jenny

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