Size of hist3 output
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Hi,
I would like to compute the a bivariate histogram by specifying the bin boundaries rather than centers. I've beed doing this with the hist3 function by specifying bin edges. I am wounding why the output of hist3 is size length(edges{1}) x length(edges{2}) rather than length(edges{1})-1 x length(edges{2})-1. Typically x number of specified bin boundaries give x-1 number of bins. Can anyone clarify this to me?
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Jan
on 27 Sep 2013
See e.g. the help text of histc:
N(k) will count the value X(i) if EDGES(k) <= X(i) < EDGES(k+1). The
last bin will count any values of X that match EDGES(end).
Therefore you get k results for k-1 intervals.
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