Asked by Arun Sharma
on 7 Oct 2013

Hello!!! Everyone,

I am making a Data Logger Project and had stored Log in Memory Card, and wants to plot the Temperature Data with Respect to time in MATLAB.

18:41:03,05/10/13,025.7C,+024.5C,060.0%,000.00m/s,0,0000.0mm,0000.0mm 18:41:17,05/10/13,025.7C,+024.8C,060.0%,000.00m/s,0,0000.0mm,0000.0mm 18:41:32,05/10/13,025.4C,+024.8C,059.3%,000.00m/s,0,0000.0mm,0000.0mm 18:41:48,05/10/13,025.7C,+025.1C,059.3%,000.00m/s,0,0000.0mm,0000.0mm 18:29:50,05/10/13,026.0C,+024.8C,059.0%,000.00m/s,0,0000.0mm,0000.0mm 18:30:04,05/10/13,025.7C,+024.8C,058.7%,000.00m/s,0,0000.0mm,0000.0mm

18:30:04-> Time 05/10/13-> Date 025.7C -> Unit Temperature +024.8C -> Atmosphere Temperature 058.7% -> Relative Humidity

Rest are Not useful

Can any one tell how to plot Temperature w.r.t time for each day on Separate graphs(Figure in MATLAB)

Please Help

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Answer by Walter Roberson
on 7 Oct 2013

Accepted answer

fid - fopen('YourFile.txt'); datacell = textscan(fid, '%s%s%fC%fC%f%*[^\n]', 'Delimiter', ','); fclose(datacell);

fulldates = strcat(datacell{2}, {' '}, datacell{1}); datenumbers = datenum(fulldates, 'mm/dd/yy HH:MM:SS');

unittemps = datacell{3}; atmtemps = datacell{4}; relhums = datecell{5};

fig1 = figure(); ax1 = axes('Parent', fig1); plot(datenumbers, unittemps, 'Parent', ax1); datetick(ax1, 'x', 'HH:MM:SS'); title(ax1, 'Time vs Unit Temperature, Uni');

The refinement after this would be to split it down to individual days. For example as a quick hack:

datechars = char(datacell{2}); differentdates = any(diff(datchars, 1), 2);

Then differentdates will be true at location K if the K'th date differs from the (K+1)'th date and so indicates that you should split *after* the K'th row. Note that the result will be one element shorter than the number of row entries.

Answer by Arun Sharma
on 7 Oct 2013

Edited by Walter Roberson
on 7 Oct 2013

I had attached the file, and its not working

I found some errors like

fid = fopen('YourFile.txt'); datacell = textscan(fid, '%s%s%fC%fC%f%*[^\n]', 'Delimiter', ','); fclose(fid);

I will try to use your code.

Can i use datetick function in MATLAB for solving my problem

Walter Roberson
on 7 Oct 2013

You are going to need to change the 'YourFile.txt' to 'LOGGER.CSV' .

datetick will not solve your problem by itself. Your problem has a couple of pieces:

- reading in the text and throwing away the unneeded parts
- converting the text dates into numeric dates
- breaking the input lines up by date
- plotting each day with its corresponding data on separate figure per day
- labeling the x axis of the plots with the time information

Of these tasks, datetick() only accomplishes the last, the labeling of the axis.

Arun Sharma
on 7 Oct 2013

Arun Sharma
on 10 Oct 2013

Thank You So Much, I tried your method and it works. :-)

Here is the Code i wrote.

fid = fopen('LOGGER.CSV','r'); DataCell = textscan(fid,'%s %s %fC %fC %f%*[^\n]',1329,'Delimiter',',') FullDate = strcat(DataCell{2},{' '},DataCell{1}) DateNumbers = datenum(FullDate,'mm/dd/yy HH:MM:SS') UnitTemp = DataCell{3} AtmTemp = DataCell{4} Humidity = DataCell{5} fig figure1 fig1 = figure(); ax1 = axes('Parent',fig1) plot(DateNumbers,UnitTemp,'Parent',ax1); grid on axis([min(DateNumbers) max(DateNumbers) 20 30]) datetick(ax1,'x','HH:MM') xlabel('Time\rightarrow'); ylabel('Temperature \rightarrow'); title('Temperature Graph 5th October'); fclose(fid);

Can You Explain me the meaning of this line

DataCell = textscan(fid,'%s %s %fC %fC %f%*[^\n]',1329,'Delimiter',',')

This part [^\n], although i know what it is doing but still wants to know this notation.

And Also the meaning of this line.

ax1 = axes('Parent',fig1)

Thank You Much, You method is perfect one.

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