to which command refers ~isempty() to?

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Manuel Olschner
Manuel Olschner on 14 Oct 2013
Commented: Jan on 14 Oct 2013
Sorry for the dumb question, but I am working on a matlab code I didn't write myself and several '~isempty(<1xn> cell in here)' are occuring. Since I am relatively new to matlab and programming, I just don't understand yet to what the isempty refers. I couldn't find any satisfying answers and so i thought maybe i could find help here. The isempty is always bound to an if loop.
like:
set (handles. ...
set (handles. ...
if ~isempty(ZoneElementProtNameUnder{1,1})
set(handles.protUnder,'String',ZoneElementProtNameUnder{1,1});
else ...
So does isempty work with the 'set handles' or with the 'ZoneElement...', or even with a previous command? Or what exactly is it doing?
I appreciate any answers or help, thanks!

Accepted Answer

Cedric
Cedric on 14 Oct 2013
Edited: Cedric on 14 Oct 2013
ZoneElementProtNameUnder is a 2D cell array. ZoneElementProtNameUnder{1,1} is the content of cell on column 1 and row 1 (curly brackets = "content of" for cell arrays). As cells can have empty content, the condition in the IF statement
if ~isempty(ZoneElementProtNameUnder{1,1})
is just checking that this cell's content is not empty. If true, then the expression
set(handles.protUnder,'String',ZoneElementProtNameUnder{1,1});
is using the content.

More Answers (1)

Walter Roberson
Walter Roberson on 14 Oct 2013
In that code, ZoneElementProtNameUnder is a cell array that has at least one element. To access just that one element unwrapped from the cell array, you would code ZoneElementProtNameUnder{1,1} . If the entity that is stored there is empty, then isempty(ZoneElementProtNameUnder{1,1}) would be true, and ~isempty(ZoneElementProtNameUnder{1,1}) would be false; contrawise if ZoneElementProtNameUnder{1,1} had something in it, then isempty(ZoneElementProtNameUnder{1,1}) would be false and ~isempty(ZoneElementProtNameUnder{1,1}) would be true.
  2 Comments
Manuel Olschner
Manuel Olschner on 14 Oct 2013
that explains it very well, thank you!
Jan
Jan on 14 Oct 2013
@Cedric and Walter: I appreciate your clear explanations of this basic question.

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