How do I find the number of "star" points in a Central Composite Design in the Statistics Toolbox?

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Accepted Answer

MathWorks Support Team
MathWorks Support Team on 27 Jun 2009
The points that provide the extremes of the factors are known as the "star points." Suppose the value of the extreme is A. In this case,
A=sqrt(2)
would be appropriate for a design having two factors. For N factors, it is a N-dimensional sphere, rather than a square passing through the corners of the cube. If that were the only consideration, we would use
A=sqrt(N)
In fact, though, there is a criterion known as "rotatability" that dictates we should set A=N^(1/4), where N is the number of points in the cube portion of the design.
For 14 factors, a full factorial would have 2^14 points in the cube. The CCDESIGN function instead uses a half fraction of the full factorial, so N is half of this value, and A is
star = ((2^14) / 2) ^ (1/4)
To know how many star points are generated for a 14 factor design:
Dc=ccdesign(14,'type','circumscribed');
star=((2^14) / 2) ^ (1/4);
ind =find(abs((Dc(:,:))==star));
"ind" tells you that there are exactly 14 star points.

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