Problem 106. Weighted average

Created by Will

Given two lists of numbers, determine the weighted average.

[1 2 3] and [10 15 20]

should result in

33.3333  (1*10 + 2*15 + 3*20)/3

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1281 solvers submitted 2830 solutions (2.21 solutions/solver).

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Israel on 27 Jan 2012

weighted mean should really be sum(x.*w)/sum(w), and not as defined in the problem.

Davide Ferraro on 27 Jan 2012

I agree with the definition above. You need to define the sum of all the weights and not the number of weights.

John D'Errico on 17 Feb 2012

As the others have said, the problem title is flat out wrong. What is required is simply not a weighted average in any standard form.

William Smith on 25 Sep 2012

Come on Mathworks, delete this problem!

Solution Comments

Solution 176733

1 Comment

sea knowledge on 13 Dec 2012

l doubt on this definition of the problem

Solution 138106

1 Comment

J.G. on 11 Sep 2012

This is not the Weighted average. One should divide by the sum of the weighs, not by the number of them.

Solution 116371

1 Comment

Dimosthenis on 20 Jul 2012

This is not the weighted average. The weighted average has the sum of w in the denominator

Solution 65516

2 Comments

Mohammed on 24 Mar 2012

I submitted a correct code with correct outputs , yet it keeps returning that its wrong i donno how to report that

Freddy on 25 Mar 2012

input - Request user input, thus values for x and w were overwritten.

Solution 55083

1 Comment

Andrew Davis on 2 Mar 2012

This probably shouldn't pass...

Solution 4105

1 player likes this solution

1 Comment

Jan Simon on 28 Jan 2012

I like the commented "y =(x*w.')/length(x)" more than the "shorter" solution.

Problem 106. Weighted average

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1281 solvers submitted 2830 solutions (2.21 solutions/solver).

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