Cody

Solution 194982

Submitted on 22 Jan 2013 by J.R.! Menzinger
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Test Suite

Test Status Code Input and Output
1   Pass
%% F = @(n,k)(sin(n)+sin(k)) G = @(n,k)(n+k) n = 6; k = 4; y_correct = false; assert(isequal(wzpair(F,G,n,k),y_correct))
F = @(n,k)(sin(n)+sin(k)) G = @(n,k)(n+k) ans = 0
2   Pass
%% F = @(n,k) (((-1)^k)*nchoosek(n,k)*nchoosek(2*k,k)*4^(n-k)/nchoosek(2*n,n)); G = @(n,k)((2*k-1)*F(n,k-1)/(2*n+1)) n = 7; k = 2; y_correct = true; assert(isequal(wzpair(F,G,n,k),y_correct))
G = @(n,k)((2*k-1)*F(n,k-1)/(2*n+1)) ans = 1
3   Pass
%% F = @(n,k)(sin(n)+sin(k)) G = @(n,k)(n+k) n = 7; k = 2; y_correct = false; assert(isequal(wzpair(F,G,n,k),y_correct))
F = @(n,k)(sin(n)+sin(k)) G = @(n,k)(n+k) ans = 0
4   Pass
%% F = @(n,k) (((-1)^k)*nchoosek(n,k)*nchoosek(2*k,k)*4^(n-k)/nchoosek(2*n,n)); G = @(n,k)((2*k-1)*F(n,k-1)/(2*n+1)) n = 6; k = 4; y_correct = true; assert(isequal(wzpair(F,G,n,k),y_correct))
G = @(n,k)((2*k-1)*F(n,k-1)/(2*n+1)) ans = 1