Cody

# Problem 1732. GJam: 2013 Rd1a Bullseye Painting - Large Numbers

Solution 286604

Submitted on 22 Jul 2013 by Tobias Schäfer
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### Test Suite

Test Status Code Input and Output
1   Pass
%% tic r=uint64(308436464205151562); pmax=uint64(1850618785230909388); rings=solve_rings(r,pmax); assert(isequal(rings,3),sprintf('rings=%i, Expected 3',rings))

``` x = @(r0,K)(2*K+2*r0-1)*K ```

2   Pass
%% r=uint64(760961177192651897); pmax=uint64(1521922354385303795); rings=solve_rings(r,pmax); assert(isequal(rings,1),sprintf('rings=%i, Expected 1',rings))

``` x = @(r0,K)(2*K+2*r0-1)*K ```

3   Pass
%% r=uint64(1); pmax=uint64(2000000000000000000); rings=solve_rings(r,pmax); assert(isequal(rings,999999999),sprintf('rings=%i, Expected 999999999',rings))

``` x = @(r0,K)(2*K+2*r0-1)*K ```

4   Pass
%% r=uint64(1000); pmax=uint64(2000000000000000000); rings=solve_rings(r,pmax); assert(isequal(rings,999999500),sprintf('rings=%i, Expected 999999500',rings))

``` x = @(r0,K)(2*K+2*r0-1)*K ```

5   Pass
%% r=uint64(3); pmax=uint64(1243678947483597075); rings=solve_rings(r,pmax); assert(isequal(rings,788567988),sprintf('rings=%i, Expected 788567988',rings))

``` x = @(r0,K)(2*K+2*r0-1)*K ```

6   Pass
%% r=uint64(432); pmax=uint64(1800692162794074077); rings=solve_rings(r,pmax); assert(isequal(rings,948865465),sprintf('rings=%i, Expected 948865465',rings)) toc

``` x = @(r0,K)(2*K+2*r0-1)*K Elapsed time is 0.039589 seconds. ```