Cody

# Problem 1961. Finding neighbors of [-1:1] in a matrix....

Hello All!

Well I found this one fun to figure out, all you have to do is make a matrix of 1's or 0's (true or false) that show whether or not a number in a matrix is sitting directly next to (a neighbor) that is number that is +1 or -1 or == to that of the original number. Here are some examples:

```M1 = [1 2 1;
5 6 7;
2 3 6]
```

SO now find numbers next to one another that are +1 of each-other.

```output = [1 1 1;
1 1 1;
1 1 1]
One more:
```
```M2 = [8 8 8;
4 4 4;
1 9 7]
```

SO now find numbers next to one another that are +1 of each-other.

```output = [1 1 1;
1 1 1;
0 0 0]
```

One more:

```M3 = [1  8   5;
4  10  22;
1  66  7]
```

SO now find numbers next to one another that are +1 of each-other.

```output = [0 0 0;
0 0 0;
0 0 0]
```

Well good luck!

### Solution Stats

76.47% Correct | 23.53% Incorrect
Last solution submitted on Feb 11, 2015

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