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Problem 201. Mimic foldl in functional programming

Created by S L

Mimic the higher-order function foldl ( Wikipedia:Fold (higher-order function) ).

Arguments are a function with two arguments, start value, and a list. It takes the start value and the first item in the list and then applies the function to them, then feeds the function with this result and the second item in the list, and so on.

    foldl(f, start, [x1, x2, ..., xn]) == f( (...f(f(f(s, x1), x2), x3), ...) , xn)
    foldl(@plus, 0, 1:10) == ( ... (((0 + 1) + 2) + 3) + ... + 10) == 55

If the list is missing, it have to return the function handle which takes list. If both the start value and the list are missing, it have to return the function handle which takes two arguments, start value and list.

    sumplusfive = foldl(@plus, 5);
    => sumplusfive(1:10) == 60
    concat = foldl(@(x_, y_) [x_ y_]);
    => concat([1 2 3], [4 5 6]) == [1 2 3 4 5 6]

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Solution Statistics

62 correct solutions 75 incorrect solutions
Last solution submitted on Apr 23, 2016

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