Cody

Problem 2170. Dealfun (1.0)

Short description.

Write a function dealfun:

[y1,y2,...,yn]=dealfun(fhandle,x1,x2,...,xn)

which evaluates the function handle fhandle on arguments x1,x2,...,xn independently and deal solutions to outputs y1,y2,...,yn (so nargin==nargout+1)

Long description.

Several repetitions of exacly same operation on different variables can be a pain in the neck when you are editing your code.

a=a^2+mod(a,3);       a=a^3+4*a+mod(a,3);
b=b^2+mod(a,3);  -->  b=b^3+4*a+mod(a,3);
c=c^2+mod(a,3);       c=c^3+4*a+mod(a,3);
d=d^2+mod(a,3);       d=d^3+4*a+mod(a,3);

Of course there are as many strategies as programmers. There are also many helpful functions like cellfun arrayfun deal feval. But sometimes usage of those functions in one line looks unclear and it doesn't make editing faster. Usage of dealfun could look like that:

funh=@(A)A^2+mod(A,3);   -->   funh=@(A)A^3+4*A+mod(A,3);
[a,b,c,d]=dealfun(@funh,a,b,c,d);

example:

>> [a,b,c,d]=dealfun(@sum,ones(1),ones(2),ones(3),ones(4))
a =  1
b =  2     2
c =  3     3     3
d =  4     4     4     4

easy change:

>> [a,b,c,d]=dealfun(@numel,ones(1),ones(2),ones(3),ones(4))
a =  1
b =  4
c =  9
d =  16

Solution Stats

66.67% Correct | 33.33% Incorrect
Last solution submitted on Oct 29, 2016

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