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Problem 240. Project Euler: Problem 6, Natural numbers, squares and sums.

Created by Doug Hull

The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first N (where N is the input) natural numbers and the square of the sum.

Thank you to Project Euler Problem 6

Problem Group

Solution Statistics

327 correct solutions 178 incorrect solutions
Last solution submitted on Oct 07, 2014

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