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The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first N (where N is the input) natural numbers and the square of the sum.

Thank you to Project Euler Problem 6

360 correct solutions
197 incorrect solutions

Last solution submitted on Apr 22, 2015

1 Comment

Daniel Pereira
on 8 May 2014

I think simpler is impossible. The only thing is that it needs 8 operations...
:(

2 Comments

William Smith
on 25 Sep 2012

For loops, not cool!

Doug Hull
on 26 Sep 2012

William, Why are for loops not cool?

1 Comment