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Solution 261136

Submitted on 14 Jun 2013 by Dan

Correct

18Size
Leading solution size is 18.
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

Test Suite

Test
Code Input and Output
1
Pass
 
%%
assert(isequal(nonuniformQuantizer(-23), -3.5));
ans =
   -3.5000
2
Pass
 
%%
assert(isequal(nonuniformQuantizer(0), 0.5));
ans =
    0.5000
3
Pass
 
%%
assert(isequal(nonuniformQuantizer(1.1), 1.5));
ans =
    1.5000
4
Pass
 
%%
assert(isequal(nonuniformQuantizer(2.9), 1.5));
ans =
    1.5000
5
Pass
 
%%
assert(isequal(nonuniformQuantizer(-Inf), -3.5));
ans =
   -3.5000
6
Pass
 
%%
assert(isequal(nonuniformQuantizer(Inf), 3.5));
ans =
    3.5000
7
Pass
 
%%
x = -4.0:0.5:4.5;
y = [-3.5 -3.5 -1.5 -1.5 -1.5 ...
    -1.5 -0.5 -0.5 0.5 0.5 1.5 ...
    1.5 1.5 1.5 3.5 3.5 3.5 3.5];
assert(isequal(y, nonuniformQuantizer(x)));
ans =
  Columns 1 through 10
   -3.5000   -3.5000   -1.5000   -1.5000   -1.5000   -1.5000   -0.5000   -0.5000    0.5000    0.5000
  Columns 11 through 18
    1.5000    1.5000    1.5000    1.5000    3.5000    3.5000    3.5000    3.5000
8
Pass
 
%%
x = -4.0:0.5:4.5;
y = [-3.5 -3.5 -1.5 -1.5 -1.5 ...
    -1.5 -0.5 -0.5 0.5 0.5 1.5 ...
    1.5 1.5 1.5 3.5 3.5 3.5 3.5];
assert(isequal(y', nonuniformQuantizer(x')));
ans =
   -3.5000
   -3.5000
   -1.5000
   -1.5000
   -1.5000
   -1.5000
   -0.5000
   -0.5000
    0.5000
    0.5000
    1.5000
    1.5000
    1.5000
    1.5000
    3.5000
    3.5000
    3.5000
    3.5000
9
Pass
 
%%
x = -4.0:0.5:4.5;
y = [-3.5 -3.5 -1.5 -1.5 -1.5 ...
    -1.5 -0.5 -0.5 0.5 0.5 1.5 ...
    1.5 1.5 1.5 3.5 3.5 3.5 3.5];
assert(isequal(reshape(y,3,6), ...
    nonuniformQuantizer(reshape(x,3,6))));
ans =
   -3.5000   -1.5000   -0.5000    0.5000    1.5000    3.5000
   -3.5000   -1.5000   -0.5000    1.5000    1.5000    3.5000
   -1.5000   -1.5000    0.5000    1.5000    3.5000    3.5000
10
Pass
 
%%
x = -4.0:0.5:4.5;
y = [-3.5 -3.5 -1.5 -1.5 -1.5 ...
    -1.5 -0.5 -0.5 0.5 0.5 1.5 ...
    1.5 1.5 1.5 3.5 3.5 3.5 3.5];
assert(isequal(reshape(y,1,6,3), ...
    nonuniformQuantizer(reshape(x,1,6,3))));
ans(:,:,1) =
   -3.5000   -3.5000   -1.5000   -1.5000   -1.5000   -1.5000
ans(:,:,2) =
   -0.5000   -0.5000    0.5000    0.5000    1.5000    1.5000
ans(:,:,3) =
    1.5000    1.5000    3.5000    3.5000    3.5000    3.5000