Cody

# Problem 365. Numbers with prime factors 2, 3 and 5.

Solution 261393

Submitted on 14 Jun 2013 by andrea84
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
%% n = 2; A_correct = 2; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 ans = 2 ```

2   Pass
%% n = 3; A_correct = [2 3]; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 c = 0 1 1 ans = 2 3 ```

3   Pass
%% n = 4; A_correct = [2 3 4]; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 c = 0 1 1 c = 0 1 1 1 ans = 2 3 4 ```

4   Pass
%% n = 5; A_correct = [2 3 4 5]; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 c = 0 1 1 c = 0 1 1 1 c = 0 1 1 1 1 ans = 2 3 4 5 ```

5   Pass
%% n = 10; A_correct = [2 3 4 5 6 8 9 10]; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 c = 0 1 1 c = 0 1 1 1 c = 0 1 1 1 1 c = 0 1 1 1 1 1 c = 0 1 1 1 1 1 0 c = 0 1 1 1 1 1 0 1 c = 0 1 1 1 1 1 0 1 1 c = 0 1 1 1 1 1 0 1 1 1 ans = 2 3 4 5 6 8 9 10 ```

6   Pass
%% n = 17; A_correct = [2 3 4 5 6 8 9 10 12 15 16]; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 c = 0 1 1 c = 0 1 1 1 c = 0 1 1 1 1 c = 0 1 1 1 1 1 c = 0 1 1 1 1 1 0 c = 0 1 1 1 1 1 0 1 c = 0 1 1 1 1 1 0 1 1 c = 0 1 1 1 1 1 0 1 1 1 c = 0 1 1 1 1 1 0 1 1 1 0 c = 0 1 1 1 1 1 0 1 1 1 0 1 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 0 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Column 17 0 ans = 2 3 4 5 6 8 9 10 12 15 16 ```

7   Pass
%% n = 31; A_correct = [2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 30]; assert(isequal(your_fcn_name(n),A_correct))

``` c = 0 c = 0 1 c = 0 1 1 c = 0 1 1 1 c = 0 1 1 1 1 c = 0 1 1 1 1 1 c = 0 1 1 1 1 1 0 c = 0 1 1 1 1 1 0 1 c = 0 1 1 1 1 1 0 1 1 c = 0 1 1 1 1 1 0 1 1 1 c = 0 1 1 1 1 1 0 1 1 1 0 c = 0 1 1 1 1 1 0 1 1 1 0 1 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 0 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 c = 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Column 17 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 18 0 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 19 0 1 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 20 0 1 0 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 21 0 1 0 1 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 22 0 1 0 1 0 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 23 0 1 0 1 0 0 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 24 0 1 0 1 0 0 0 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 25 0 1 0 1 0 0 0 1 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 26 0 1 0 1 0 0 0 1 1 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 27 0 1 0 1 0 0 0 1 1 0 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 28 0 1 0 1 0 0 0 1 1 0 1 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 29 0 1 0 1 0 0 0 1 1 0 1 0 0 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 30 0 1 0 1 0 0 0 1 1 0 1 0 0 1 c = Columns 1 through 16 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 1 Columns 17 through 31 0 1 0 1 0 0 0 1 1 0 1 0 0 1 0 ans = Columns 1 through 16 2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 27 Column 17 30 ```