Given n and m, construct an n-by-n matrix a such that a, when rotated 90 degrees and compared with itself, matches itself in exactly m places.
The number of matches m is calculated as follows:
m = nnz(rot90(a)==a)
Your answer a is clearly not unique. It must only meet the criteria stated above.
Input n = 2, m = 1 One possible output: a = [ 1 2 1 3 ]
Input n = 3, m = 7 One possible output: a = [ 0 1 1 1 1 1 1 1 1 ]
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