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Schwarz-Christoffel Toolbox

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from Schwarz-Christoffel Toolbox by Toby Driscoll
Computes conformal maps to polygons, allowing easy solution of Laplace's equation.

extermap(varargin)
function map = extermap(varargin)
%EXTERMAP Schwarz-Christoffel exterior map object.
%   EXTERMAP(P) constructs a Schwarz-Christoffel exterior map object for
%   the polygon P. The parameter problem is solved using default options
%   for the prevertices and the multiplicative constant.
%   
%   EXTERMAP(P,OPTIONS) uses an options structure of the type created by
%   SCMAPOPT in solving the parameter problem.
%   
%   EXTERMAP(P,Z) creates a extermap object having the given prevertices
%   Z (the mulitiplicative constant is found automatically).
%   EXTERMAP(P,Z,C) also uses the given constant. An OPTIONS argument
%   can be added, although only the error tolerance will be used.
%   
%   EXTERMAP(M), where M is a extermap object, just returns M.
%   
%   EXTERMAP(M,P) returns a new extermap object for the polygon P using
%   the options in extermap M. The prevertices of M will be used as the
%   starting guess for the parameter problem of the new map. Thus P
%   should properly be a perturbation of the polygon for M. An OPTIONS
%   structure may also be given to override options in M.
%   
%   EXTERMAP(Z,ALPHA) creates a map using the given prevertices and the
%   interior polygon angles described by ALPHA (see POLYGON help). The
%   image polygon is deduced by computing S-C integrals assuming a
%   multiplicative constant of 1. EXTERMAP(Z,ALPHA,C) uses the given
%   constant instead. Note that not every pairing of prevertices and
%   angles produces a single-valued map; you must have SUM((ALPHA-1)./Z)
%   equal to zero. Also, Z is given counterclockwise around the unit
%   circle, but ALPHA should be clockwise with respect to the interior
%   of the polygon.
%   
%   See also SCMAPOPT, classes POLYGON, SCMAP.

%   Copyright 1998-2001 by Toby Driscoll.
%   $Id: extermap.m 129 2001-05-07 15:04:13Z driscoll $

superiorto('double');

if nargin == 0
  map.prevertex = [];
  map.constant = [];
  map.qdata = [];
  map.accuracy = [];
  parent = scmap;
  map = class(map,'extermap',parent);
  return
end

% Initialize with empties
poly = [];
alpha = [];
z = [];
c = [];
opt = [];
qdata = [];

% Branch based on class of first argument
switch class(varargin{1})
  case 'extermap'
    map = varargin{1};
    if nargin == 1
      % Self-return
      return
    else
      % Continuation of given map to given polygon
      poly = varargin{2};
      opt = scmapopt(map);
      z0 = map.prevertex;
      if length(z0) ~= length(poly)
        msg = 'Polygon %s must have the same length as that in %s.';
        error(sprintf(msg,inputname(2),inputname(1)))
      end
      if nargin > 2
        opt = scmapopt(opt,varargin{3});
      end
      opt = scmapopt(opt,'initial',z0);
    end
    
  case 'polygon'
    poly = varargin{1};
    % Parse optional arguments
    for j = 2:length(varargin)
      arg = varargin{j};
      % Each arg is an options struct, z, or c
      if isa(arg,'struct')
        opt = arg;
      elseif length(arg) == length(poly)
        z = arg;
        % We will have to flip vertices to get correct orientation
        z = flipud(z(:));
      elseif length(arg) == 1
        c = arg;
      else
        msg = 'Unable to parse argument ''%s''.';
        error(sprintf(msg,inputname(j+1)))
      end
    end
    
  case 'double'
    % Args are the prevertex vector, then angle vector
    z = varargin{1}(:);
    alpha = varargin{2};
    poly = polygon(NaN*alpha*i,alpha);
    c = 1;
    % Check residue of integrand to see if compatible
    if abs(sum((alpha-1)./z)) > 1e-8
      error('Map is not single-valued')
    end
    for j = 3:length(varargin)
      if isa(varargin{j},'struct')
        opt = varargin{j};
      elseif length(varargin{j})==1
        c = varargin{j};
      else
        msg = 'Unable to parse argument ''%s''.';
        error(sprintf(msg,inputname(j+1)))
      end
    end
  
  otherwise
    msg = 'Expected ''%s'' to be of class polygon or extermap.';
    error(sprintf(msg,inputname(1)))
end % switch


% Retrieve options
opt = scmapopt(opt);

% Take actions based on what needs to be filled in

if isempty(z)
  % Find prevertices
  % Apply SCFIX to enforce solver rules
  w = flipud(vertex(poly));
  beta = 1 - flipud(angle(poly));
  [w,beta] = scfix('de',w,beta);
  poly = polygon(flipud(w),1-flipud(beta));

  z0 = opt.InitialGuess;
  tol = opt.Tolerance;
  [z,c,qdata] = deparam(w,beta,z0,opt);
end

if isempty(qdata)
  % Base quadrature accuracy on given options
  nqpts = ceil(-log10(opt.Tolerance));
  beta = 1 - flipud(angle(poly));
  qdata = scqdata(beta,nqpts);
end

if isempty(c)
  % Find constant
  w = flipud(vertex(poly));
  beta = 1 - flipud(angle(poly));
  mid = z(1)*exp(i*angle(z(2)/z(1))/2);
  I = dequad(z(1),mid,1,z,beta,qdata) - dequad(z(2),mid,2,z,beta,qdata);
  c = diff(w(1:2))/I;
end
  
map.prevertex = z;
map.constant = c;
map.qdata = qdata;

% Make a parent scmap object
parent = scmap(poly,opt);

% Leave a spot for accuracy and create object
map.accuracy = [];
if ~isa(map,'extermap')
  map = class(map,'extermap',parent);
else
  map.scmap = parent;
end

% If the polygon was not known, find it from the map
if any(isnan(vertex(poly)))
  poly = forwardpoly(map);
  map.scmap = scmap(poly,opt);
end

% Now fill in apparent accuracy
map.accuracy = accuracy(map);

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