DATEPART

Extract decimal yr/month/day/hr/min/sec from a datenum. More versatile than datevec.

Description

X = DATEPART(DATE,'part') returns the date 'part' (year, month,day, hour, minute or second) of the datenum date with the decimal equivalent of the trailing date parts in the units of 'part'. DATE can be scalar, vector or array and X will be of the some size and shape.

  [X1,X2,...] = DATEPART(DATE,'part1','part2',...) returns each decimal value corresponding to each part input argument.

  Acceptable string specifiers for 'part' are:
  Year: 'year','yr','years','yrs'
  Month: 'month','mn','months','mns'
  Day: 'day','days'
  Hour: 'hour','hours','hr','hrs'
  Minute: 'minutes','minutes','min','mins'
  Second: 'second','seconds','sec','secs'

  Examples:
  >> A = datenum('14-Jul-2007 15:05:12')
  >> datepart(A,'min')
  ans =
       5.2000
  >> floor(datepart(A,'min'))
  ans =
      5
  >> format bank
  >> datepart(A,'year')
  ans =
      2007.53
  >> [day,yr] = datepart(A,'day','year')
  day =
         14.63
  yr =
       2007.53

• MATLAB release: MATLAB 7.2 (R2006a)

[Cory Sieg]

Doesn't pick out the month accurately from a daily time series.

[Ian Howat]

Cory,
Please give some more details of your error *BEFORE* trashing the function with a 1-star rating so that I can fix it. You say a that the function is failing in returning the correct month with a 1-day time series. If I create such as time series with:
>t = datenum('jan-0-2008')+(1:365);
and then sample this time series about once a month:
>> ts = t(1:30:end);
>> datestr(ts)
ans =
01-Jan-2008
31-Jan-2008
01-Mar-2008
31-Mar-2008
30-Apr-2008
30-May-2008
29-Jun-2008
29-Jul-2008
28-Aug-2008
27-Sep-2008
27-Oct-2008
26-Nov-2008
26-Dec-2008

and then get the decimal month using datepart:
>> datepart(ts,'month')
ans =
  Columns 1 through 9
    1.0000 1.9677 3.0000 3.9677 4.9667 5.9355 6.9333 7.9032 8.8710
  Columns 10 through 13
    9.8667 10.8387 11.8333 12.8065
Looks good to me ... sure you're using it correctly??????