function S=csfit(X,Y,dx0,dxn)
%Input - X is the 1xn abscissa vector
% - Y is the 1xn ordinate vector
% - dxo = S'(x0) first derivative boundary condition
% - dxn = S'(xn) first derivative boundary condition
%Output - S: rows of S are the coefficients for the cubic interpolants
% NUMERICAL METHODS: MATLAB Programs
%(c) 1999 by John H. Mathews and Kurtis D. Fink
%To accompany the textbook:
%NUMERICAL METHODS Using MATLAB,
%by John H. Mathews and Kurtis D. Fink
%ISBN 0-13-270042-5, (c) 1999
%PRENTICE HALL, INC.
%Upper Saddle River, NJ 07458
N=length(X)-1;
H=diff(X);
D=diff(Y)./H;
A=H(2:N-1);
B=2*(H(1:N-1)+H(2:N));
C=H(2:N);
C=H(2:N);
U=6*diff(D);
%Clamped spline endpoint constraints
B(1)=B(1)-H(1)/2;
U(1)=U(1)-3*(D(1)-dx0);
B(N-1)=B(N-1)-H(N)/2;
U(N-1)=U(N-1)-3*(dxn-D(N));
for k=2:N-1
temp=A(k-1)/B(k-1);
B(k)=B(k)-temp*C(k-1);
U(k)=U(k)-temp*U(k-1);
end
M(N)=U(N-1)/B(N-1);
for k=N-2:-1:1
M(k+1)=(U(k)-C(k)*M(k+2))/B(k);
end
%Clamped spline endpoint constraints
M(1)=3*(D(1)-dx0)/H(1)-M(2)/2;
M(N+1)=3*(dxn-D(N))/H(N)-M(N)/2;
for k=0:N-1
S(k+1,1)=(M(k+2)-M(k+1))/(6*H(k+1));
S(k+1,2)=M(k+1)/2;
S(k+1,3)=D(k+1)-H(k+1)*(2*M(k+1)+M(k+2))/6;
S(k+1,4)=Y(k+1);
end