% [val, num] = howmany(x)
%
% counts the number of occurrences of finite values in x
%
% in: x vector of nnumbers (array will be reshaped to a vector)
%
% out: val unique values in x, sorted
% num number of occurrences
It would be nice if this checked for floating point differences as well.
Ex:
a = [0 0.1 0.2 0.3 0.4];
b = [0:0.1:0.4];
>> [v n] =howmany([a b])
%%%%%%%%%%%%%
v =
0
0.1
0.2
0.3
0.3
0.4
n =
2
2
2
1
1
2
Because the arrays a and b are essentially equal (within eps):
%%%%%%%%%%
>> abs(a-b)<eps
ans =
1 1 1 1 1
>> isequal(a,b)
ans =
0
%%%%%%%%%%
you should at least give an option to count them as the same number.
The exact equal match is intentional in this function. I have another function: "isclose" for the "close enough" comparisons.
But a good suggestion anyway, I might add that option.
